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Ch. 2 - Transmission Genetics
Sanders - Genetic Analysis: An Integrated Approach 3rd Edition
Sanders3rd EditionGenetic Analysis: An Integrated ApproachISBN: 9780135564172Not the one you use?Change textbook
Chapter 2, Problem 39b

A cross between a spicy variety of Capsicum annum pepper and a sweet (nonspicy) variety produces F1 progeny plants that all have spicy peppers. The F1 are crossed, and among the F2 plants are 56 that produce spicy peppers and 20 that produce sweet peppers. Dr. Ara B. Dopsis, an expert on pepper plants, discovers a gene he designates Pun1 that he believes is responsible for spicy versus sweet flavor of peppers. Dr. Dopsis proposes that a dominant allele P produces spicy peppers and that a recessive mutant allele p results in sweet peppers.
Assuming the proposal is correct, what proportion of the spicy F2 pepper plants do you expect will be pure-breeding? Explain your answer.

Verified step by step guidance
1
Start by identifying the genetic basis of the problem. The spicy flavor is controlled by a dominant allele (P), while the sweet flavor is controlled by a recessive allele (p). This means that plants with genotypes PP or Pp will produce spicy peppers, and plants with genotype pp will produce sweet peppers.
Determine the expected genotypic ratio in the F₂ generation. Since the F₁ generation is heterozygous (Pp) for all plants, a cross between two heterozygous plants (Pp × Pp) will produce offspring in the ratio 1:2:1 (PP:Pp:pp).
Calculate the phenotypic ratio in the F₂ generation. Based on the genotypic ratio, the phenotypes will be 3 spicy (PP and Pp) to 1 sweet (pp). This matches the observed data of 56 spicy and 20 sweet plants, as the ratio 56:20 simplifies approximately to 3:1.
Focus on the spicy plants (PP and Pp) and determine the proportion that are pure-breeding. Pure-breeding spicy plants have the genotype PP. From the genotypic ratio (1:2:1), the proportion of PP among the spicy plants (PP and Pp) is 1/(1+2) = 1/3.
Conclude that 1/3 of the spicy F₂ pepper plants are expected to be pure-breeding (PP). This is because the genotypic ratio of PP:Pp among spicy plants is 1:2, and only the PP plants are pure-breeding.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Dominant and Recessive Alleles

In genetics, alleles are different forms of a gene that can exist at a specific locus on a chromosome. A dominant allele, represented by a capital letter (e.g., P), masks the effect of a recessive allele (e.g., p) when both are present in a heterozygous individual. This means that if at least one dominant allele is present, the dominant trait will be expressed in the phenotype, while the recessive trait will only be expressed if two recessive alleles are present.
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Punnett Square

A Punnett square is a diagram used to predict the genotypes of offspring from a genetic cross. It allows for the visualization of how alleles from each parent combine to form the possible genotypes of the progeny. By filling in the squares based on the alleles contributed by each parent, one can determine the expected ratios of dominant and recessive traits in the offspring, which is crucial for understanding inheritance patterns.
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Pure-Breeding

Pure-breeding refers to organisms that consistently produce offspring with the same phenotype when crossed with each other. In the context of the pepper plants, a pure-breeding spicy pepper plant would have the genotype PP, while a pure-breeding sweet pepper plant would have the genotype pp. Understanding the concept of pure-breeding is essential for predicting the proportion of offspring that will exhibit a specific trait, especially when considering the F2 generation resulting from a cross between heterozygous parents.
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Related Practice
Textbook Question

Galactosemia is an autosomal recessive disorder caused by the inability to metabolize galactose, a component of the lactose found in mammalian milk. Galactosemia can be partially managed by eliminating dietary intake of lactose and galactose. Amanda is healthy, as are her parents, but her brother Alonzo has galactosemia. Brice has a similar family history. He and his parents are healthy, but his sister Brianna has galactosemia. Amanda and Brice are planning a family and seek genetic counseling. Based on the information provided, complete the following activities and answer the questions.


If the first child has galactosemia, what is the probability that the second child will have galactosemia? Explain the reasoning for your answer.

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Textbook Question

Sweet yellow tomatoes with a pear shape bring a high price per basket to growers. Pear shape, yellow color, and terminal flower position are recessive traits produced by alleles f, r, and t, respectively. The dominant phenotypes for each trait—full shape, red color, and axial flower position—are the product of dominant alleles F, R, and T. A farmer has two pure-breeding tomato lines. One is full, yellow, terminal and the other is pear, red, axial. Design a breeding experiment that will produce a line of tomato that is pure-breeding for pear shape, yellow color, and axial flower position.

634
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Textbook Question

A cross between a spicy variety of Capsicum annum pepper and a sweet (nonspicy) variety produces F1 progeny plants that all have spicy peppers. The F1 are crossed, and among the F2 plants are 56 that produce spicy peppers and 20 that produce sweet peppers. Dr. Ara B. Dopsis, an expert on pepper plants, discovers a gene he designates Pun1 that he believes is responsible for spicy versus sweet flavor of peppers. Dr. Dopsis proposes that a dominant allele P produces spicy peppers and that a recessive mutant allele p results in sweet peppers.

Are the data on the parental cross and the F1 and F2 consistent with the proposal made by Dr. Dopsis? Explain why or why not, using P and p to indicate probable genotypes of pepper plants.

417
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Textbook Question

Alkaptonuria is an infrequent autosomal recessive condition. It is first noticed in newborns when the urine in their diapers turns black upon exposure to air. The condition is caused by the defective transport of the amino acid phenylalanine through the intestinal walls during digestion. About 4 people per 1000 are carriers of alkaptonuria.

Sara and James had never heard of alkaptonuria and were shocked to discover that their first child had the condition. Sara's sister Mary and her husband, Frank, are planning to have a family and are concerned about the possibility of alkaptonuria in one of their children.

The four adults (Sara, James, Mary, and Frank) seek information from a neighbor who is a retired physician. After discussing their family histories, the neighbor says, "I never took genetics, but I know from my many years in practice that Sara and James are both carriers of this recessive condition. Since their first child had the condition, there is a very low chance that the next child will also have it, because the odds of having two children with a recessive condition are very low. Mary and Frank have no chance of having a child with alkaptonuria because Frank has no family history of the condition." The two couples each have babies and both babies have alkaptonuria.


What are the genotypes of the four adults?

701
views
Textbook Question

Alkaptonuria is an infrequent autosomal recessive condition. It is first noticed in newborns when the urine in their diapers turns black upon exposure to air. The condition is caused by the defective transport of the amino acid phenylalanine through the intestinal walls during digestion. About 4 people per 1000 are carriers of alkaptonuria.

Sara and James had never heard of alkaptonuria and were shocked to discover that their first child had the condition. Sara's sister Mary and her husband, Frank, are planning to have a family and are concerned about the possibility of alkaptonuria in one of their children.

The four adults (Sara, James, Mary, and Frank) seek information from a neighbor who is a retired physician. After discussing their family histories, the neighbor says, 'I never took genetics, but I know from my many years in practice that Sara and James are both carriers of this recessive condition. Since their first child had the condition, there is a very low chance that the next child will also have it, because the odds of having two children with a recessive condition are very low. Mary and Frank have no chance of having a child with alkaptonuria because Frank has no family history of the condition.' The two couples each have babies and both babies have alkaptonuria.


What was incorrect about the information given to Sara and James? What is incorrect about the information given to Mary and Frank?

541
views
Textbook Question

Alkaptonuria is an infrequent autosomal recessive condition. It is first noticed in newborns when the urine in their diapers turns black upon exposure to air. The condition is caused by the defective transport of the amino acid phenylalanine through the intestinal walls during digestion. About 4 people per 1000 are carriers of alkaptonuria.

Sara and James had never heard of alkaptonuria and were shocked to discover that their first child had the condition. Sara's sister Mary and her husband, Frank, are planning to have a family and are concerned about the possibility of alkaptonuria in one of their children.

The four adults (Sara, James, Mary, and Frank) seek information from a neighbor who is a retired physician. After discussing their family histories, the neighbor says, 'I never took genetics, but I know from my many years in practice that Sara and James are both carriers of this recessive condition. Since their first child had the condition, there is a very low chance that the next child will also have it, because the odds of having two children with a recessive condition are very low. Mary and Frank have no chance of having a child with alkaptonuria because Frank has no family history of the condition.' The two couples each have babies and both babies have alkaptonuria.


What is the probability that the second child of Mary and Frank will have alkaptonuria?

425
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