Complete the following equations:
c.

Question

Complete the following equations:

c. Chemical equation showing a cyclic amine reacting with hydrochloric acid, with a question mark indicating an incomplete reaction.

Accepted Answer

All right. Hi, everyone. So this question is asking us what is the complete equation for the following reaction? And here we have Pyro Aine reacting with hydrogen Broma. So we have paladine and hydrogen bromide or simply H pr. Now recall first and foremost that Perrodin is a neutral amine which are characteristically considered weak base. And HBR is known to be a strong asset. So recall that the reaction involving a weak base and a strong acid is known as neutralization. This is going to be an example of a neutralization reaction. So to understand the products that are going to be formed. In this case, we have to recall very briefly, the Brony Lary acid based definition, we call it bronzed diary acids, proce acids donate protons. So they themselves lose that proton in the process whereas bases except the protons donated by the bronci acid. Now, the reason why Perrodin here or any neutral amine for that matter can behave as a base is because nitrogen has low pairs of electrons. So in this case, the proton from hydrogen bromide is going to transfer from the acid to the base. So let's go ahead and draw out the product, my products are not necessarily going to change their structure drastically comparing the structure of palain to the corresponding product. The structure of the ring, for example, is not going to change. The main difference here is that nitrogen is going to have two hydrogens attached to it instead of one at the very beginning. Now recall that this is also going to affect the charge because for every proton that is gained, the charge of the species is going to increase by one. So if nitrogen had no charge in the beginning and it gained a proton, the charge has since increased to positive one. So in the product here, which is the pol odium ion, nitrogen is now positive. And on the other hand, right, bromine in hydrogen bromide has since lost a proton. So because it's lost a proton, the charge has decreased from zero or neutral to negative one. So my product here would be or another product would be bromide or br negative. So in this case, right, our product is referred to as an ammonium salt with the ammonium ion referring to the species that contains a positive charge on nitrogen. And so bromide therefore is the counter ion of the ammonium salt ensuring that the compound remains neutral overall and there you have it. And so here we have an example of a neutralization reaction involving a weak base Peridin and a strong acid H pr to produce paladium bromide which is an ammonium salt. And so with all that being said, thank you so very much for watching. And I hope you found this helpful.

Complete the following equations:
c.

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