Complete the following equations:
a.

Question

Complete the following equations:

a. Chemical equation showing an amine reacting with aqueous HBr, with a question mark indicating an incomplete reaction.

Accepted Answer

All right. Hi, everyone. So this question is asking us to provide the complete equation for the following reaction involving N 23 dry metal butan to amine and hydrogen chloride or simply HC. Now, in this case, right, recall that a means like the one pictured on the screen here are characteristically weak bases when they are neutral. So neutral, amines are weak base. Whereas hydrogen, hydrogen chloride, if you recall is a strong acid. So the reaction between a weak base and a strong acid is referred to as a neutralization reaction. So because our starting material or one of them is an amine, right, our product is going to be an ammonium salt. Recall that in the Bronzo dari acid based definition bases like our amen here are proton acceptors, right? They accept protons from the acid which is the proton donor. So in this case, right, nitrogen would accept a proton from the strong acid and it would gain an additional proton. Now recall that for every proton that is gained during an acid base reaction, the charge increases by one. So if the starting amine was neutral, then the ammonium salt is going to have a charge of positive one because the charge increases by one for every proton that is gained. Now, by contrast, for every proton that is lost, the charge is going to decrease by one. So considering the structure of HCL here, chlorine, right, chlorine is going to lose the proton that it has and therefore decrease the charge from zero to negative one. So in this case, we can go ahead and illustrate this with the structure that I redrew here on the bottom of the screen. So in this case, right nitrogen, because it has an extra loan pair of electrons can accept a proton donated from HC. So in this case, I'm going to actually copy the structure of my amen here because the structure of the starting amine is not going to change aside from the addition of an extra proton. So I'm going to keep the structure pretty much the same except for the fact that nitrogen gains a second hydrogen at. And so that is going to increase the charge on nitrogen from zero to positive one, the nitrogen now has a positive charge. And as discussed previously, right HCL is going to lose its proton to generate chloride or cl negative one. So in the structure of my final product goes chloride next to the nitrogen atom. The reason for this is because the positive charge on chloride is going to gravitate towards the positive charge on the nitrogen. Hence why they appear close together and there you have it right. So in this case, we have N 23 trim Meho butane, two amine, which is a weak base reacting with a strong acid like HC to produce N 23 tri methyl butane to a minium chloride in which nitrogen has a positive charge and chloride has a negative charge to balance out the charges. So with that being said, thank you so very much for watching and I hope you found this helpful.

Complete the following equations:
a.

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