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Ch. 1 - Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 1, Problem 1.1.54

Even and Odd Functions


In Exercises 47–62, say whether the function is even, odd, or neither. Give reasons for your answer.


g(x) = x/(x² − 1)

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1
To determine if a function is even, odd, or neither, we need to evaluate the function at -x and compare it to the original function g(x).
Calculate g(-x) by substituting -x into the function: g(-x) = (-x)/((-x)² - 1).
Simplify g(-x): Since (-x)² = x², we have g(-x) = -x/(x² - 1).
Compare g(-x) with g(x): g(x) = x/(x² - 1) and g(-x) = -x/(x² - 1). Notice that g(-x) = -g(x).
Since g(-x) = -g(x), the function g(x) is odd. A function is odd if g(-x) = -g(x) for all x in the domain of the function.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Even Functions

A function is classified as even if it satisfies the condition f(-x) = f(x) for all x in its domain. This means that the graph of an even function is symmetric with respect to the y-axis. A common example of an even function is f(x) = x², where substituting -x yields the same output as substituting x.
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Odd Functions

A function is considered odd if it meets the condition f(-x) = -f(x) for all x in its domain. This indicates that the graph of an odd function is symmetric with respect to the origin. An example of an odd function is f(x) = x³, where substituting -x results in the negative of the output for x.
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Function Analysis

Analyzing a function involves evaluating its behavior under transformations, such as substituting -x for x. This process helps determine whether the function is even, odd, or neither. For the function g(x) = x/(x² - 1), one must compute g(-x) and compare it to g(x) and -g(x) to classify its symmetry.
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