Use the formula for nPr to evaluate each expression. ₆P₆

Verified step by step guidance

1. Recall the formula for permutations: \(nP_r = \frac{n!}{(n-r)!}\), where \(n\) is the total number of items and \(r\) is the number of items to arrange.
2. Identify the values of \(n\) and \(r\) in the expression \$6P6\(. Here, \)n = 6\( and \)r = 6$.
3. Substitute these values into the formula: \$6P6 = \frac{6!}{(6-6)!}$.
4. Simplify the denominator: \((6-6)! = 0!\). Remember that by definition, \$0! = 1$.
5. The expression now becomes \$6P6 = \frac{6!}{1} = 6!\(. To find the value, you would calculate \)6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1$, but the problem only asks for the setup.

Key Concepts

Permutation Formula (nPr)

The permutation formula nPr calculates the number of ways to arrange r objects from a set of n distinct objects, where order matters. It is given by nPr = n! / (n - r)!, where '!' denotes factorial.

Factorial Notation

Factorial, denoted by n!, is the product of all positive integers from 1 up to n. For example, 6! = 6 × 5 × 4 × 3 × 2 × 1 = 720. Factorials are essential in permutations and combinations calculations.

Evaluating nPr When r = n

When the number of objects chosen r equals the total number n, nPr simplifies to n!, because (n - n)! = 0! = 1. Thus, nPn = n!, representing all possible arrangements of the entire set.