Write a balanced chemical equation using condensed structural formulas for

a. the formation of butyl propionate from the appropriate acid and alcohol

Video transcript

All right. Hello everyone. So this question is asking us to write the balanced chemical equation of the reaction of a carboxylic acid and an alcohol to form iso butter propionate. This is a certification and also used condensed formula just to go ahead and clarify. Recall that the condensed formula of an organic molecule showcases how atoms are bonded without necessarily showing all of the bonds. For example, when trying to simplify the parent chain of an organic compound, oftentimes carbon and hydrogen atoms are grouped together in blocks. For example, ch three represents three hydrogens attached to one carbon and then we also have C two and C and so on. So here the given reaction is an example of aeration in which a carboxylic acid combines with an alcohol to produce an ester. The ether in question is Isobel propionate. And recall that when naming an ester, the portion of the molecule that comes from the alcohol is listed first, followed by the portion that came from the carboxylic acid. So our parent chain, which is the second word here is propionate, which comes from propo OIC acid. So that's a three carbon chain with the car bal on position one. And so the carbonel on position one and we have an additional oxygen from the carboxylic acid. And now ester and so branching off of the single bonded oxygen in our ester is the Isobel substituent. So the iso beetle group is a three carbon chain with an additional metal group branching off of the third carbon farthest away from the car bal. However, because we're using condensed formulas, the third carbon of the chain, as well as the methyl substituent can be abbreviated as two ch three units. So from here, let's go ahead and talk about are reactants. Once again, this is a stir application. So here to create the ester that was given to us in the beginning of this video, we have to separate the carboxylic acid group from the alcohol group. This means that I'm going to imagine breaking the bond in between the single bonded oxygen and the first carbon of the Isobel group. And so after breaking this bond between oxygen and carbon, adding a hydrogen to oxygen, create a carboxylic acid. So here, one of our reagents is C three zh two coo H which is propionic acid or propo OIC acid. So now the question is what to do about the remaining carbon chain because the remaining carbon chain that is the Isobel group came from the alcohol. I'm going to go ahead and attach a hydroxy group that's an O group onto the carbon. That was initially bonded to the carboxylic acid oxygen. So that's or I still beat over it with a hydroxy group at the end, this means that our reagents are two methyl propane, one oil and propionic acid. So I am going to go ahead and modify the structure of our Esther. The showcase botha carbonel and the single bonded oxygens as two oxygens within the greater chain. And I'm going to go ahead and make this smaller just so that I can fit my reactions or my reagents, excuse me. And so here is our reaction and I do want to point out that another product of aeration is water. So I'm going to make sure to add that as well. And so from here, our last step is to go ahead and balance out the chemical equation. However, this is already balanced. So our synthesis is complete and there you have it. So with that being said, thank you so very much for watching and I hope you found this helpful.