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Ch.4 - Reactions in Aqueous Solution
Chapter 4, Problem 59

What is the volume of the solution that would result by diluting 70.00 mL of 0.0913 M NaOH to a concentration of 0.0150 M?

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Identify the initial concentration \( C_1 = 0.0913 \text{ M} \) and initial volume \( V_1 = 70.00 \text{ mL} \).
Identify the final concentration \( C_2 = 0.0150 \text{ M} \).
Use the dilution formula: \( C_1 \times V_1 = C_2 \times V_2 \).
Substitute the known values into the equation: \( 0.0913 \times 70.00 = 0.0150 \times V_2 \).
Solve for \( V_2 \) to find the final volume of the solution.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Dilution

Dilution is the process of reducing the concentration of a solute in a solution, typically by adding more solvent. The relationship between the initial and final concentrations and volumes of a solution can be described by the dilution equation, C1V1 = C2V2, where C1 and V1 are the initial concentration and volume, and C2 and V2 are the final concentration and volume.
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Molarity

Molarity (M) is a measure of concentration defined as the number of moles of solute per liter of solution. It is a crucial concept in chemistry for quantifying how much solute is present in a given volume of solution, allowing for calculations involving reactions, dilutions, and solution preparations.
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Conservation of Mass

The principle of conservation of mass states that mass is neither created nor destroyed in a chemical reaction. In the context of dilution, this means that the amount of solute before dilution (moles of NaOH) remains constant, allowing us to relate the initial and final states of the solution through the dilution equation.
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