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Ch. 25 - Quantitative Genetics and Multifactorial Traits
Klug - Concepts of Genetics  12th Edition
Klug12th EditionConcepts of Genetics ISBN: 9780135564776Not the one you use?Change textbook
Chapter 25, Problem 4c

A dark-red strain and a white strain of wheat are crossed and produce an intermediate, medium-red F₁. When the F₁ plants are interbred, an F₂ generation is produced in a ratio of 1 dark-red: 4 medium-dark-red: 6 medium-red: 4 light-red: 1 white. Further crosses reveal that the dark-red and white F₂ plants are true breeding
Assign symbols to these alleles, and list possible genotypes that give rise to the medium-red and light-red phenotypes.

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1
Step 1: Recognize that the inheritance pattern described is an example of incomplete dominance, where the heterozygote shows an intermediate phenotype between the two homozygotes. The parental strains are dark-red and white, and the F₁ is medium-red, an intermediate color.
Step 2: Assign allele symbols to the two alleles involved. For example, let \( R_d \) represent the dark-red allele and \( R_w \) represent the white allele. Since the F₁ is intermediate, the heterozygote \( R_d R_w \) shows medium-red color.
Step 3: Analyze the F₂ phenotypic ratio: 1 dark-red : 4 medium-dark-red : 6 medium-red : 4 light-red : 1 white. This suggests multiple genotypic classes with varying dosages of the alleles, indicating that the trait is controlled by more than one allele or by gene dosage effects.
Step 4: Propose genotypes for each phenotype based on allele dosage. The homozygotes \( R_d R_d \) and \( R_w R_w \) correspond to dark-red and white, respectively (true breeding). The intermediate phenotypes (medium-dark-red, medium-red, light-red) likely correspond to heterozygotes with different combinations or dosages of the alleles, such as \( R_d R_w \), \( R_d R_d R_w \), or \( R_d R_w R_w \) if multiple alleles or gene copies are involved.
Step 5: Specifically list possible genotypes for medium-red and light-red phenotypes. For example, medium-red could be the simple heterozygote \( R_d R_w \), while light-red could be a genotype with more white allele dosage, such as \( R_d R_w R_w \) or a similar combination depending on the genetic model.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Incomplete Dominance

Incomplete dominance occurs when heterozygous individuals display a phenotype intermediate between the two homozygous parents. In this wheat example, the F₁ medium-red color results from blending of dark-red and white alleles, rather than one being completely dominant over the other.
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Variations on Dominance

Genotype-Phenotype Relationship and Allele Symbol Assignment

Assigning symbols to alleles helps track inheritance patterns. Typically, the darkest phenotype is assigned the dominant allele (e.g., R), the lightest the recessive (e.g., r), and intermediate phenotypes arise from heterozygous or multiple allele combinations. Understanding which genotypes correspond to each phenotype is key.
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Non-Random Mating

F₂ Phenotypic Ratios and True Breeding

The F₂ generation's phenotypic ratio reflects the segregation and combination of alleles. True breeding plants (dark-red and white) are homozygous, confirming allele assignments. The complex 1:4:6:4:1 ratio suggests multiple allele interactions or codominance, requiring analysis of genotype combinations for intermediate phenotypes.
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Mendel's Experiments
Related Practice
Textbook Question

Define the following:

(a) Polygenic

(b) Additive alleles

(c) Correlation

(d) Monozygotic and dizygotic twins

(e) Heritability

(f) QTL

(g) Continuous variation

625
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Textbook Question

A dark-red strain and a white strain of wheat are crossed and produce an intermediate, medium-red F₁. When the F₁ plants are interbred, an F₂ generation is produced in a ratio of 1 dark-red: 4 medium-dark-red: 6 medium-red: 4 light-red: 1 white. Further crosses reveal that the dark-red and white F₂ plants are true breeding

Based on the ratios in the F₂ population, how many genes are involved in the production of color?

463
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Textbook Question

A dark-red strain and a white strain of wheat are crossed and produce an intermediate, medium-red F₁. When the F₁ plants are interbred, an F₂ generation is produced in a ratio of 1 dark-red: 4 medium-dark-red: 6 medium-red: 4 light-red: 1 white. Further crosses reveal that the dark-red and white F₂ plants are true breeding

How many additive alleles are needed to produce each possible phenotype?

436
views
Textbook Question

A dark-red strain and a white strain of wheat are crossed and produce an intermediate, medium-red F₁. When the F₁ plants are interbred, an F₂ generation is produced in a ratio of 1 dark-red: 4 medium-dark-red: 6 medium-red: 4 light-red: 1 white. Further crosses reveal that the dark-red and white F₂ plants are true breeding

Predict the outcome of the F1 and F2 generations in a cross between a true-breeding medium-red plant and a white plant.

721
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Textbook Question

Height in humans depends on the additive action of genes. Assume that this trait is controlled by the four loci R, S, T, and U and that environmental effects are negligible. Instead of additive versus nonadditive alleles, assume that additive and partially additive alleles exist. Additive alleles contribute two units, and partially additive alleles contribute one unit to height.

Can two individuals of moderate height produce offspring that are much taller or shorter than either parent? If so, how?

914
views
Textbook Question

Height in humans depends on the additive action of genes. Assume that this trait is controlled by the four loci R, S, T, and U and that environmental effects are negligible. Instead of additive versus nonadditive alleles, assume that additive and partially additive alleles exist. Additive alleles contribute two units, and partially additive alleles contribute one unit to height.

If an individual with the minimum height specified by these genes marries an individual of intermediate or moderate height, will any of their children be taller than the tall parent? Why or why not?

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