Work backward to show how the cyclopropane would be synthesized from the chloroalkane shown.

Verified step by step guidance

1. Step 1: Identify the target molecule (cyclopropane derivative) and the starting material (benzyl chloride). The goal is to synthesize the cyclopropane ring from the chloroalkane through a series of reactions.
2. Step 2: Recognize that the formation of a cyclopropane ring typically involves a carbene or carbenoid intermediate. To generate this intermediate, the chloroalkane can undergo deprotonation to form a carbanion, followed by reaction with a reagent like CH2I2 (diiodomethane) in the presence of Zn/Cu to form the cyclopropane ring.
3. Step 3: Consider the stereochemistry of the target molecule. The (+/-) notation indicates the formation of a racemic mixture, meaning both enantiomers of the cyclopropane are formed. This suggests that the reaction mechanism does not favor one stereoisomer over the other.
4. Step 4: Plan the reaction sequence. First, treat the benzyl chloride with a strong base (e.g., NaOH or KOH) to form the benzyl carbanion. Next, react the carbanion with diiodomethane (CH2I2) in the presence of Zn/Cu to generate the cyclopropane ring.
5. Step 5: Verify the reaction conditions and intermediates. Ensure that the reagents used (base, CH2I2, Zn/Cu) are appropriate for the formation of the cyclopropane ring and that the stereochemistry aligns with the racemic mixture observed in the product.

Key Concepts

Cyclopropane Synthesis

Cyclopropane can be synthesized through various methods, including the reaction of alkenes with reagents that facilitate cyclization. One common approach is the use of a chloroalkane, which can undergo nucleophilic substitution or elimination reactions to form the cyclopropane structure. Understanding the mechanisms of these reactions is crucial for determining the synthetic pathway.

Nucleophilic Substitution

Nucleophilic substitution is a fundamental reaction in organic chemistry where a nucleophile attacks an electrophilic carbon atom, replacing a leaving group. In the context of synthesizing cyclopropane from a chloroalkane, this process can involve the formation of a cyclic intermediate, which is essential for constructing the three-membered ring characteristic of cyclopropane.

Elimination Reactions

Elimination reactions involve the removal of atoms or groups from a molecule, resulting in the formation of a double bond or a ring structure. In synthesizing cyclopropane, elimination can occur from a chloroalkane to generate an alkene, which can then undergo further reactions to form the cyclopropane. Understanding the conditions and mechanisms of elimination is vital for successful synthesis.