At launch a rocket ship weighs $4.5$ million pounds. When it is launched from rest, it takes $8.00$ s to reach $161$ km/h; at the end of the first $1.00$ min, its speed is $1610$ km/h. What is the average acceleration (in m/s²) of the rocket (i) during the first $8.00$ s and (ii) between $8.00$ s and the end of the first $1.00$ min?

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Hello everyone zones problem. The bullet shaped ride in an amusement park raised about £11,000 at its full capacity from rest. It starts moving upwards from the ground. For safety purposes. It needs to be slow at first and it takes 10 seconds to reach eight m per second At the end of two minutes. Speed is 40 m/s. And we want to calculate the acceleration During the 1st 10 seconds between seconds. So for this first part we know that the average acceleration, it's just the change in velocity over the change in time during that time, During this time period is between 10 seconds and zero seconds. So the final time period is 10 seconds. The initial time period is zero seconds, final velocity, It's eight m for a second. The initial velocity is zero m. So we get that the average acceleration in this first part, 0.8 m through 2nd square 2nd part. We can take the same approach. It's just delta V delta T. You have, It's 40 m/s and V R. Is the velocity at this 12th point which is eight m per second, Delta T or TF is equal to two minutes. We need to convert two minutes and two seconds by doing a simple speculation By seconds for a minute, which gives us 120 Final time. There's one in 20 seconds time period in the seconds And it gives us an average acceleration of 0.29. Yeah, just a second. So in the first part is .8. The second part is 291, so we know the answer choices. Hope This one have a great day.

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Key Concepts

Acceleration

Unit Conversion

Kinematics