In one day, a -kg mountain climber ascends from the -m level on a vertical cliff to the top at m. The next day, she descends from the top to the base of the cliff, which is at an elevation of m. What is her change in gravitational potential energy on the first day?
Ch 07: Potential Energy & Conservation
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 7, Problem 12
Tarzan, in one tree, sights Jane in another tree. He grabs the end of a vine with length m that makes an angle of with the vertical, steps off his tree limb, and swings down and then up to Jane's open arms. When he arrives, his vine makes an angle of with the vertical. Determine whether he gives her a tender embrace or knocks her off her limb by calculating Tarzan's speed just before he reaches Jane. Ignore air resistance and the mass of the vine.
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Step 1: Identify the energy conservation principle. Since air resistance and the mass of the vine are ignored, we can use the conservation of mechanical energy. Tarzan's potential energy at the starting point is converted into kinetic energy and potential energy at the final point.
Step 2: Write the expression for Tarzan's potential energy at the starting point. The height difference between Tarzan's initial position and the lowest point of the swing can be calculated using the vine length and the angle with the vertical. Use the formula for height: \( h = L(1 - \cos\theta) \), where \( L \) is the vine length and \( \theta \) is the angle with the vertical.
Step 3: Write the expression for Tarzan's potential energy at the final point. Similarly, calculate the height difference between Tarzan's final position and the lowest point of the swing using \( h = L(1 - \cos\theta) \), where \( \theta \) is the final angle with the vertical.
Step 4: Apply the conservation of mechanical energy. The total mechanical energy at the starting point (potential energy) is equal to the total mechanical energy at the final point (kinetic energy + potential energy). Use the equation: \( m g h_{initial} = \frac{1}{2} m v^2 + m g h_{final} \), where \( m \) is Tarzan's mass, \( g \) is the acceleration due to gravity, \( h_{initial} \) is the initial height, \( h_{final} \) is the final height, and \( v \) is Tarzan's speed just before reaching Jane.
Step 5: Solve for Tarzan's speed \( v \). Rearrange the equation to isolate \( v \): \( v = \sqrt{2 g (h_{initial} - h_{final})} \). Substitute the values for \( g \), \( h_{initial} \), and \( h_{final} \) to calculate Tarzan's speed. Ensure all units are consistent.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Conservation of Energy
The principle of conservation of energy states that the total energy in a closed system remains constant. In the context of Tarzan's swing, potential energy at the highest point converts to kinetic energy at the lowest point. This relationship allows us to calculate Tarzan's speed just before he reaches Jane by equating the potential energy lost to the kinetic energy gained.
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Kinematics of Circular Motion
When Tarzan swings on the vine, he undergoes circular motion. The angle of the vine with the vertical affects the radius of the circular path and the forces acting on him. Understanding the kinematics involved, including the relationship between angular displacement and linear speed, is crucial for determining his speed at different points in the swing.
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Forces and Acceleration
The forces acting on Tarzan during his swing include gravitational force and tension in the vine. As he swings down, gravity accelerates him, and the tension provides the necessary centripetal force to keep him moving in a circular path. Analyzing these forces helps in calculating the net acceleration and ultimately Tarzan's speed just before he reaches Jane.
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