Commercial concentrated aqueous ammonia is 28% NH 3 by mass and has a density of 0.90 g/mL. What is the molarity of this solution?

Step 1: Understand the problem. We are asked to find the molarity of a solution. Molarity (M) is defined as the number of moles of solute per liter of solution. In this case, the solute is NH 3 (ammonia) and the solution is the mixture of NH 3 and water.. Step 2: Calculate the mass of NH 3 in 1 liter of solution. Since the density of the solution is 0.90 g/mL, the mass of 1 liter (or 1000 mL) of solution is 0.90 g/mL * 1000 mL = 900 g. Since the solution is 28% NH 3 by mass, the mass of NH 3 in this 1 liter of solution is 28% * 900 g = 0.28 * 900 g.. Step 3: Convert the mass of NH 3 to moles. The molar mass of NH 3 is approximately 17.03 g/mol. So, the number of moles of NH 3 is the mass of NH 3 divided by the molar mass of NH 3 .. Step 4: Calculate the molarity. The molarity (M) is the number of moles of solute (NH 3 ) per liter of solution. Since we have calculated the number of moles of NH 3 in 1 liter of solution in the previous step, this number is the molarity of the solution.. Step 5: Check your answer. The molarity should be a positive number and have the unit of moles per liter (M). If your answer has the correct unit and is a reasonable number, it is likely to be correct.

Commercial concentrated aqueous ammonia is 28% NH 3 by mass and has a density of 0.90 g/mL. What is the molarity of this solution?

Hey everyone, we're told at 25 degrees Celsius a 32% by mass. Hydrochloric solution has a density of 1.161 g per mil. Leader Expresses concentration in molar itty first we need to recognize that 32% mass of hydrochloric solution essentially means that we have 32.0 g of hydrochloric acid In 100 g of solution. Since we have a total of 100%. So that means we have 100 g of our solution. Now to calculate our polarity, we need to calculate our moles of hydrochloric acid and our volume. So starting off with our moles of hydrochloric acid, we're going to take 32.0 g of hydrochloric acid And using dimensional analysis And our molar mass of hydrochloric acid, we know that we have 36.458g of hydrochloric acid, Her one mole of hydrochloric acid. So when we calculate this up, We end up with a value of 0. mol of hydrochloric acid. So now let's go ahead and calculate the volume of our solution. Starting off with 100 g of solution, We're going to use dimensional analysis again and we're going to take the density which is 1.161 g of solution per one millimeter. But since polarity is calculated in leaders, we have to convert our milliliters into leaders. So we have 10 to the third milliliters or one leader. So when we calculate this out, we end up with a volume of 0.0861 leaders. Now we can go ahead and calculate our polarity Again. Our polarity is going to be our moles of solute, which is 0.8777 mol of hydrochloric acid, divided by our leaders of solution, which is 0.0861 leaders. So when we calculate this out, we end up with a polarity of 10.2 molar, which is going to be our final answer. Now. I hope that made sense and let us know if you have any questions.

Commercial concentrated aqueous ammonia is 28% NH3 by mass and has a density of 0.90 g/mL. What is the molarity of this solution?

Step 1: Understand the problem. We are asked to find the molarity of a solution. Molarity (M) is defined as the number of moles of solute per liter of solution. In this case, the solute is NH 3 (ammonia) and the solution is the mixture of NH 3 and water. Step 2: Calculate the mass of NH 3 in 1 liter of solution. Since the density of the solution is 0.90 g/mL, the mass of 1 liter (or 1000 mL) of solution is 0.90 g/mL * 1000 mL = 900 g. Since the solution is 28% NH 3 by mass, the mass of NH 3 in this 1 liter of solution is 28% * 900 g = 0.28 * 900 g. Step 3: Convert the mass of NH 3 to moles. The molar mass of NH 3 is approximately 17.03 g/mol. So, the number of moles of NH 3 is the mass of NH 3 divided by the molar mass of NH 3 . Step 4: Calculate the molarity. The molarity (M) is the number of moles of solute (NH 3 ) per liter of solution. Since we have calculated the number of moles of NH 3 in 1 liter of solution in the previous step, this number is the molarity of the solution. Step 5: Check your answer. The molarity should be a positive number and have the unit of moles per liter (M). If your answer has the correct unit and is a reasonable number, it is likely to be correct.

Ch.13 - Properties of Solutions

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Brown 14th Edition

Ch.13 - Properties of Solutions

Problem 56

Chapter 13, Problem 56

Commercial concentrated aqueous ammonia is 28% NH₃ by mass and has a density of 0.90 g/mL. What is the molarity of this solution?

Verified step by step guidance

Step 1: Understand the problem. We are asked to find the molarity of a solution. Molarity (M) is defined as the number of moles of solute per liter of solution. In this case, the solute is NH₃ (ammonia) and the solution is the mixture of NH₃ and water.

Step 2: Calculate the mass of NH₃ in 1 liter of solution. Since the density of the solution is 0.90 g/mL, the mass of 1 liter (or 1000 mL) of solution is 0.90 g/mL * 1000 mL = 900 g. Since the solution is 28% NH₃ by mass, the mass of NH₃ in this 1 liter of solution is 28% * 900 g = 0.28 * 900 g.

Step 3: Convert the mass of NH₃ to moles. The molar mass of NH₃ is approximately 17.03 g/mol. So, the number of moles of NH₃ is the mass of NH₃ divided by the molar mass of NH₃.

Step 4: Calculate the molarity. The molarity (M) is the number of moles of solute (NH₃) per liter of solution. Since we have calculated the number of moles of NH₃ in 1 liter of solution in the previous step, this number is the molarity of the solution.

Step 5: Check your answer. The molarity should be a positive number and have the unit of moles per liter (M). If your answer has the correct unit and is a reasonable number, it is likely to be correct.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L) and is crucial for understanding how much solute is present in a given volume of solution. To calculate molarity, one must know the amount of solute in moles and the total volume of the solution in liters.

Density

Density is the mass of a substance per unit volume, typically expressed in grams per milliliter (g/mL) or kilograms per cubic meter (kg/m³). In this context, the density of the ammonia solution allows us to convert between mass and volume, which is essential for determining how much solution is present when calculating molarity.

Percent by Mass

Percent by mass is a way to express the concentration of a solution, indicating the mass of solute present in a given mass of solution. In this case, a 28% by mass ammonia solution means that there are 28 grams of NH₃ in every 100 grams of the solution. This information is vital for calculating the number of moles of solute when combined with the density of the solution.