What is the molar concentration of As(III) in a solution if 22.35 mL of 0.100 M KBrO3 is needed for complete reaction with 50.00 mL of the As(III) solution? The balanced equation is:

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Identify the balanced chemical equation for the reaction between As(III) and KBrO3.

Determine the stoichiometry of the reaction from the balanced equation to find the mole ratio between KBrO3 and As(III).

Calculate the moles of KBrO3 used in the reaction using the formula: \( \text{moles} = \text{concentration} \times \text{volume} \). Remember to convert the volume from mL to L.

Use the mole ratio from the balanced equation to calculate the moles of As(III) that reacted.

Calculate the molar concentration of As(III) by dividing the moles of As(III) by the volume of the As(III) solution in liters.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity

Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (M). Understanding molarity is essential for calculating the concentration of a substance in a solution, especially when dealing with reactions where volumes and concentrations of reactants are involved.

Stoichiometry

Stoichiometry is the branch of chemistry that deals with the relationships between the quantities of reactants and products in a chemical reaction. It involves using balanced chemical equations to determine how much of each substance is consumed or produced. In this question, stoichiometry is crucial for relating the volume and concentration of KBrO3 to the concentration of As(III) in the solution.

Balanced Chemical Equation

A balanced chemical equation represents a chemical reaction with equal numbers of each type of atom on both sides of the equation. It provides the mole ratios needed to relate the amounts of reactants and products. In this case, the balanced equation will allow us to determine how the moles of KBrO3 used relate to the moles of As(III) present in the solution, which is necessary for calculating its molar concentration.

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