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Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure
Chapter 8, Problem 29

Three of the following molecular models have a tetrahedral central atom, and one does not. Which is the odd one? (There may be a 'hidden' atom directly behind a visible atom in some cases.) (a)
(b)
(c)
(d)

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1
Identify the central atom in each molecular model (a, b, c, d). The central atom is typically the one bonded to multiple other atoms.
Count the number of atoms directly bonded to each central atom. A tetrahedral geometry typically involves a central atom bonded to four other atoms.
Consider the possibility of lone pairs on the central atom. A central atom with four bonds and no lone pairs generally adopts a tetrahedral shape.
Visualize or sketch the molecular geometry based on the number of bonds and lone pairs. A tetrahedral shape has bond angles of approximately 109.5 degrees.
Compare the geometries of the central atoms in options (a), (b), (c), and (d). The one that does not fit the criteria of having four bonds and no lone pairs on the central atom is the odd one out.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Tetrahedral Geometry

Tetrahedral geometry occurs when a central atom is bonded to four other atoms, forming a shape where the bonds are directed towards the corners of a tetrahedron. This arrangement minimizes electron pair repulsion according to VSEPR theory, resulting in bond angles of approximately 109.5 degrees. Understanding this geometry is crucial for identifying which molecular models exhibit a tetrahedral structure.
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VSEPR Theory

Valence Shell Electron Pair Repulsion (VSEPR) theory is a model used to predict the geometry of individual molecules based on the repulsion between electron pairs in the valence shell of the central atom. According to this theory, the spatial arrangement of atoms is determined by the need to minimize repulsion between electron pairs, which helps in predicting molecular shapes, including tetrahedral configurations.
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Coordination Number

The coordination number refers to the number of atoms, ions, or molecules that a central atom can bond with in a complex or molecule. In the context of tetrahedral geometry, a coordination number of four indicates that the central atom is bonded to four other atoms. Identifying the coordination number is essential for determining whether a molecular model fits the tetrahedral description or is the odd one out.
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Related Practice
Textbook Question
Use the chemical structure for Tagamet, a drug used to treat peptic ulcers and heartburn, to answer questions 8 and 9.

Which orbitals overlap to form bond 2? (LO 8.5) (a) C (sp) with C (sp) (b) C (sp) with C 1sp22 (c) C 1sp22 with C 1sp22 (d) C 1sp32 with C 1sp22
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Textbook Question
The C2 molecule has a MO diagram similar to N2 (Figure 8.22a). What is the bond order of C2 and is it paramagnetic or diamagnetic? (LO 8.12) (a) Bond order = 2, diamagnetic (b) Bond order = 2, paramagnetic (c) Bond order = 0, paramagnetic (d) Bond order = 3>2, diamagnetic
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Textbook Question
What is the geometry around the central atom in each of thefollowing molecular models?(a)

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Textbook Question
The VSEPR model is a simple predictive tool that is usually,but not always, correct. Take urea, for instance, a wasteproduct excreted in animal urine:

What hybridization would you expect for the C and N atoms in urea according to the VSEPR model, and what approximate values would you expect for the various bond angles? What are the actual hybridizations and bond angles based on themolecular model shown? 1Red = O, gray = C, blue = N,ivory = H.2
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Textbook Question
The following ball-and-stick molecular model is a representationof acetaminophen, the active ingredient in such over-thecounterheadache remedies as Tylenol. 1Red = O, gray = C,blue = N, ivory = H.2(c) What is the geometry around each carbon?

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Textbook Question

The following ball-and-stick molecular model is a representation of acetaminophen, the active ingredient in such over-thecounter headache remedies as Tylenol. (Red = O, gray = C, blue = N, ivory = H.) (a) What is the formula of acetaminophen?

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