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Ch. 34 - The Wave Nature of Light: Interference and Polarization
Giancoli Douglas - Physics for Scientists and Engineers 5th edition
Giancoli Douglas5th editionPhysics for Scientists and EngineersISBN: 9780137488179Not the one you use?Change textbook
Chapter 33, Problem 24

Consider three equally spaced and equal-intensity coherent sources of light (such as adding a third slit to the two slits of Fig. 34–12). Determine the positions of minima.

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Understand the problem: We are dealing with three equally spaced and equal-intensity coherent sources of light. The goal is to determine the positions of minima in the interference pattern. Minima occur where destructive interference happens, meaning the waves from the sources cancel each other out.
Write the condition for destructive interference for three sources. For three equally spaced sources, the condition for minima is that the path difference between adjacent sources must result in a phase difference of \( \frac{2\pi}{3} \) or \( \frac{4\pi}{3} \), leading to complete cancellation.
Express the path difference in terms of the angle \( \theta \) and the wavelength \( \lambda \). The path difference between adjacent sources is given by \( d \sin \theta \), where \( d \) is the spacing between the sources. For minima, the condition becomes \( d \sin \theta = m \frac{\lambda}{3} \), where \( m \) is an integer (but not a multiple of 3).
Solve for \( \sin \theta \): Rearrange the equation to find \( \sin \theta = \frac{m \lambda}{3d} \). Here, \( m \) takes on values such as \( \pm 1, \pm 2, \pm 4, \pm 5, \dots \) (avoiding multiples of 3).
Interpret the result: The angles \( \theta \) corresponding to these values of \( m \) will give the positions of the minima in the interference pattern. To find the exact angles, substitute the known values of \( \lambda \) and \( d \) into the equation.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Interference of Light

Interference occurs when two or more coherent light waves overlap, resulting in a new wave pattern. This can lead to regions of constructive interference, where waves add together, and destructive interference, where they cancel each other out. The pattern of bright and dark spots, or fringes, is a direct result of this phenomenon.
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Path Difference

Path difference refers to the difference in distance traveled by two waves arriving at a point. For minima to occur in an interference pattern, the path difference must equal an odd multiple of half the wavelength (λ/2). This condition leads to destructive interference, resulting in dark spots on the screen.
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Conditions for Minima

The conditions for minima in a multi-slit interference pattern can be derived from the formula d sin(θ) = (m + 1/2)λ, where d is the distance between slits, θ is the angle of the minima, m is an integer (0, ±1, ±2,...), and λ is the wavelength of the light. This equation helps determine the specific angles at which dark fringes appear in the interference pattern.
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Related Practice
Textbook Question

A uniform thin film of alcohol (n = 1.36) lies on a flat glass plate (n = 1.56). When monochromatic light, whose wavelength can be changed, is incident normally, the reflected light is a minimum for λ = 492 nm and a maximum for λ = 615 nm. What is the minimum thickness of the film?

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Textbook Question

(II) Suppose a thin piece of glass is placed in front of the lower slit in Fig. 34–7 so that the two waves enter the slits 180° out of phase (Fig. 34–44). Describe in detail the interference pattern on the screen.

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Textbook Question

Show that the radius r of the mᵗʰ dark Newton’s ring, as viewed from directly above (Fig. 34–18), is given by r = √mλR where R is the radius of curvature of the curved glass surface and λ is the wavelength of light used. Assume that the thickness of the air gap is much less than R at all points and that r ≪ R . [Hint: Use the binomial expansion.]

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Textbook Question

(I) If a soap bubble is 120 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated normally by white light? Assume that n = 1.35.

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Textbook Question

In a two-slit interference experiment, the path length to a certain point P on the screen differs for one slit in comparison with the other by 1.25λ.

(a) What is the phase difference between the two waves arriving at point P?

(b) Determine the intensity at P, expressed as a fraction of the maximum intensity Iₒ on the screen.

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Textbook Question

Suppose that one slit of a double-slit apparatus is wider than the other so that the intensity of light passing through it is twice as great. Determine the intensity I as a function of position (θ) on the screen for coherent light.

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