At the surface of Jupiter's moon Io, the acceleration due to gravity is g = 1.81 g = 1.81 m/s 2 . A watermelon weighs 44.0 44.0 N at the surface of the earth. What is the watermelon's mass on the earth's surface?

Welcome back everybody. We have an apple that is sitting on the surface of the earth. And we are told that the weight of this apple is one newton and we are asked to find what the mass of this apple is, what we are going to use. The fact that our weight of an object on Earth is equal to its mass times the acceleration due to gravity. I'm gonna divide both sides by this acceleration to yield and isolate that are mass is equal to our weight, divided by our acceleration due to gravity. Let's go ahead and plug in some terms here that are mass is equal to one Newton divided by 9.8 meters per second squared, which is equal to 0.102 kg. Which converting to grams gives us 102 g corresponding to answer choice B. Thank you guys so much for watching. Hope. This video helped. We will see you all in the next one.

At the surface of Jupiter's moon Io, the acceleration due to gravity is g=1.81g = 1.81 m/s2. A watermelon weighs 44.044.0 N at the surface of the earth. What is the watermelon's mass on the earth's surface?

Step 1: Recall the relationship between weight and mass, which is given by the formula: W = m ⁢ g , where W is the weight, m is the mass, and g is the acceleration due to gravity. Step 2: Identify the values provided in the problem. The weight of the watermelon on Earth's surface is 44.0 N, and the acceleration due to gravity on Earth is approximately 9.81 m/s 2 . Step 3: Rearrange the formula to solve for mass: m = W g . Substitute the given values into the equation. Step 4: Perform the division: Divide the weight of the watermelon ( 44.0 N) by the acceleration due to gravity on Earth ( 9.81 m/s 2 ). Step 5: The result of the division will give the mass of the watermelon on Earth's surface in kilograms (kg).

Ch 04: Newton's Laws of Motion

Young & Freedman Calc - University Physics 14th Edition

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Young & Freedman Calc 14th Edition

Ch 04: Newton's Laws of Motion

Problem 19a

Chapter 4, Problem 19a

At the surface of Jupiter's moon Io, the acceleration due to gravity is $g equals 1.81$ m/s². A watermelon weighs $44.0$ N at the surface of the earth. What is the watermelon's mass on the earth's surface?

Verified step by step guidance

Step 1: Recall the relationship between weight and mass, which is given by the formula:

W = m g

, where W is the weight, m is the mass, and g is the acceleration due to gravity.

Step 2: Identify the values provided in the problem. The weight of the watermelon on Earth's surface is

44.0

N, and the acceleration due to gravity on Earth is approximately

9.81

m/s².

Step 3: Rearrange the formula to solve for mass:

m = \frac{W}{g}

. Substitute the given values into the equation.

Step 4: Perform the division: Divide the weight of the watermelon (

44.0

N) by the acceleration due to gravity on Earth (

9.81

m/s²).

Step 5: The result of the division will give the mass of the watermelon on Earth's surface in kilograms (kg).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Weight and Mass

Weight is the force exerted by gravity on an object, calculated as the product of mass and gravitational acceleration (W = mg). Mass is a measure of the amount of matter in an object and remains constant regardless of location. Understanding the distinction between weight and mass is crucial for solving problems involving gravitational forces.

Gravitational Acceleration

Gravitational acceleration is the acceleration experienced by an object due to the force of gravity acting on it. On Earth, this value is approximately 9.81 m/s², but it varies on other celestial bodies, such as Jupiter's moon Io, where it is 1.81 m/s². This concept is essential for calculating weight and understanding how it changes with different gravitational fields.

Newton's Second Law of Motion

Newton's Second Law states that the force acting on an object is equal to the mass of that object multiplied by its acceleration (F = ma). This principle is fundamental in physics for analyzing the relationship between force, mass, and acceleration, and is particularly relevant when calculating weight as a force due to gravity.

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