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Ch.16 - Acid-Base Equilibria
Chapter 16, Problem 113

Many moderately large organic molecules containing basic nitrogen atoms are not very soluble in water as neutral molecules, but they are frequently much more soluble as their acid salts. Assuming that the pH in the stomach is 2.5, indicate whether each of the following compounds would be present in the stomach as the neutral base or in the protonated form: nicotine, Kb = 7 * 10-7; caffeine, Kb = 4 * 10-14; strychnine, Kb = 1 * 10-6; quinine, Kb = 1.1 * 10-6.

Verified step by step guidance
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Step 1: Understand the problem by identifying that we need to determine whether each compound is present in the stomach as a neutral base or in its protonated form, given the pH of the stomach is 2.5.
Step 2: Recognize that the protonation of a base in an acidic environment depends on the pH and the base's Kb value. Calculate the pKa for each compound using the relation pKa = 14 - pKb.
Step 3: Compare the pKa of each compound to the pH of the stomach (2.5). If pKa > pH, the compound will be predominantly in its protonated form. If pKa < pH, it will be predominantly in its neutral base form.
Step 4: Calculate the pKa for nicotine using its Kb value: pKa = 14 - (-log(7 * 10^-7)). Repeat this calculation for caffeine, strychnine, and quinine using their respective Kb values.
Step 5: Analyze the results: For each compound, determine if the pKa is greater than or less than the stomach pH of 2.5 to conclude whether it is present as a neutral base or in the protonated form.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Acid-Base Chemistry

Acid-base chemistry involves the transfer of protons (H+) between molecules. In this context, basic nitrogen atoms in organic molecules can accept protons, becoming positively charged when protonated. The pH of a solution indicates its acidity or basicity, influencing whether a compound exists in its neutral or protonated form.
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Arrhenius Acids and Bases

pKa and Kb Relationship

The relationship between pKa and Kb is crucial for understanding the behavior of weak bases in acidic environments. The pKa is the negative logarithm of the acid dissociation constant (Ka), and Kb is the base dissociation constant. By calculating pKa from Kb, one can determine the protonation state of a compound at a given pH, such as the acidic conditions in the stomach.
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Ka and Kb Relationship

Solubility of Salts vs. Neutral Bases

The solubility of organic compounds often differs between their neutral and protonated forms. Protonated forms, such as acid salts, are generally more soluble in water due to their ionic nature, while neutral bases may be less soluble. This difference is significant in biological systems, such as the stomach, where the solubility of drugs can affect their absorption and efficacy.
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Strong vs Weak Bases
Related Practice
Textbook Question

Arrange the following 0.10 M solutions in order of increasing acidity: (i) NH4NO3, (ii) NaNO3, (iii) CH3COONH4, (iv) NaF, (v) CH3COONa.

Textbook Question
Ritalin is the trade name of a drug, methylphenidate, used to treat attention-deficit/hyperactivity disorder in young adults. The chemical structure of methylphenidate is

(a) Is Ritalin an acid or a base? An electrolyte or a nonelectrolyte?
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Textbook Question

The following observations are made about a diprotic acid H2A: (i) A 0.10 M solution of H2A has pH = 3.30. (ii) A 0.10 M solution of the salt NaHA is acidic. Which of the following could be the value of pKa2 for H2A: (i) 3.22, (ii) 5.30, (iii) 7.47, or (iv) 9.82?

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Open Question
The amino acid glycine H₂N¬CH₂¬COOH can participate in the following equilibria in water: H₂N¬CH₂¬COOH + H₂O ⇌ H₂N¬CH₂¬COO⁻ + H₃O⁺ with Ka = 4.3 × 10⁻³, and H₂N¬CH₂¬COOH + H₂O ⇌ +H₃N¬CH₂¬COOH + OH⁻ with Kb = 6.0 × 10⁻⁵. (c) What would be the predominant form of glycine in a solution with pH 13? With pH 1?
Textbook Question

The amino acid glycine (H2N–CH2–COOH) can participate in the following equilibria in water:

H2N–CH2–COOH + H2O ⇌ H2N–CH2–COO + H3O+ Ka = 4.3 × 10-3

H2N–CH2–COOH + H2O⇌ +H3N–CH2–COOH + OH- Kb = 6.0 × 10-5

(a) Use the values of Ka and Kb to estimate the equilibrium constant for the intramolecular proton transfer to form a zwitterion: H2N–CH2–COOH ⇌ +H3N–CH2–COO

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Textbook Question

The amino acid glycine (H2N–CH2–COOH) can participate in the following equilibria in water:

H2N–CH2–COOH + H2O ⇌ H2N–CH2–COO + H3O+ Ka = 4.3 × 10-3

H2N–CH2–COOH + H2O⇌ +H3N–CH2–COOH + OH- Kb = 6.0 × 10-5

(b) What is the pH of a 0.050 M aqueous solution of glycine?

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