In a titration experiment, 50.0 mL of 0.075 M acetic acid, CH₃COOH, is titrated with the 0.250 M KOH(aq) that is in the burette. The drawing shows the level of the KOH in the burette before the titration begins. What will be the burette reading at the equivalence point?

Verified step by step guidance

1. Identify the balanced chemical equation for the reaction: CH_3COOH + KOH \rightarrow CH_3COOK + H_2O.
2. Calculate the moles of acetic acid (CH_3COOH) present using the formula: \text{moles} = \text{concentration} \times \text{volume}.
3. Since the reaction is a 1:1 molar ratio, the moles of KOH required will be equal to the moles of acetic acid calculated.
4. Determine the volume of KOH needed using the formula: \text{volume} = \frac{\text{moles of KOH}}{\text{concentration of KOH}}.
5. Add the calculated volume of KOH to the initial burette reading to find the burette reading at the equivalence point.

Key Concepts

Titration

Titration is a quantitative analytical technique used to determine the concentration of a solute in a solution. It involves the gradual addition of a titrant (a solution of known concentration) to a sample solution until the reaction reaches its equivalence point, where the amount of titrant added is stoichiometrically equivalent to the amount of substance in the sample.

Equivalence Point

The equivalence point in a titration is the stage at which the amount of titrant added is exactly enough to completely neutralize the analyte solution. At this point, the moles of acid equal the moles of base, and it is often indicated by a color change in an indicator or by measuring pH. Understanding this concept is crucial for calculating the final burette reading.

Molarity and Volume Calculations

Molarity (M) is a measure of concentration defined as moles of solute per liter of solution. In titration calculations, the relationship between the molarity and volume of the acid and base solutions is used to determine the volume of titrant needed to reach the equivalence point. The formula M1V1 = M2V2 helps in calculating the required volumes based on their respective molarities.