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Ch 17: Superposition
Knight Calc - Physics for Scientists and Engineers 5th Edition
Knight Calc5th EditionPhysics for Scientists and EngineersISBN: 9780137344796Not the one you use?Change textbook
Chapter 17, Problem 34

A flute player hears four beats per second when she compares her note to a 523 Hz tuning fork (the note C). She can match the frequency of the tuning fork by pulling out the 'tuning joint' to lengthen her flute slightly. What was her initial frequency?

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Step 1: Understand the concept of beats. Beats occur when two sound waves of slightly different frequencies interfere with each other. The beat frequency is equal to the absolute difference between the two frequencies: \( f_{beat} = |f_1 - f_2| \). In this case, \( f_{beat} = 4 \, \text{Hz} \).
Step 2: Identify the known values. The frequency of the tuning fork is \( f_{tuning} = 523 \, \text{Hz} \), and the beat frequency is \( f_{beat} = 4 \, \text{Hz} \). The initial frequency of the flute, \( f_{flute} \), is unknown.
Step 3: Set up the relationship between the frequencies. Since the beat frequency is the absolute difference between the flute's frequency and the tuning fork's frequency, we can write: \( f_{beat} = |f_{flute} - f_{tuning}| \). Substituting the known values: \( 4 = |f_{flute} - 523| \).
Step 4: Solve for \( f_{flute} \). The absolute value equation \( |f_{flute} - 523| = 4 \) has two possible solutions: \( f_{flute} = 523 + 4 \) or \( f_{flute} = 523 - 4 \). This gives \( f_{flute} = 527 \, \text{Hz} \) or \( f_{flute} = 519 \, \text{Hz} \).
Step 5: Determine which frequency matches the scenario. The flute player adjusts her instrument by lengthening it, which lowers the frequency. Therefore, her initial frequency must have been \( f_{flute} = 527 \, \text{Hz} \), as pulling out the tuning joint reduces the frequency to match the tuning fork's \( 523 \, \text{Hz} \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Beats Frequency

Beats frequency occurs when two sound waves of slightly different frequencies interfere with each other, resulting in a periodic variation in amplitude. The frequency of the beats is equal to the absolute difference between the two frequencies. In this case, the flute player's note and the tuning fork's frequency create a beat frequency of four beats per second, indicating that her initial frequency is either slightly higher or lower than 523 Hz.
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Frequency and Wavelength Relationship

Frequency refers to the number of cycles of a wave that occur in one second, measured in Hertz (Hz). The relationship between frequency and wavelength is described by the equation v = fλ, where v is the speed of sound, f is the frequency, and λ is the wavelength. When the flute player adjusts the length of her flute, she changes the wavelength and thus the frequency of the sound produced, allowing her to match the tuning fork.
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Tuning Fork and Musical Pitch

A tuning fork produces a specific pitch when struck, which is determined by its frequency. The standard tuning fork for the note C has a frequency of 523 Hz. Musicians use tuning forks to ensure their instruments are in tune, as the frequency of the sound produced by an instrument must match the frequency of the tuning fork for harmonious sound. The flute player's ability to adjust her instrument's length to match this frequency is crucial for achieving the correct pitch.
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Related Practice
Textbook Question

FIGURE EX17.27 shows the circular wave fronts emitted by two wave sources. Make a table with rows labeled P, Q, and R and columns labeled r1, r2, Δr, and C/D. Fill in the table for points P, Q, and R, giving the distances as multiples of λ and indicating, with a C or a D, whether the interference at that point is constructive or destructive.

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Textbook Question

Two out-of-phase radio antennas at x=±300 m on the x-axis are emitting 3.0 MHz radio waves. Is the point (x, y) =(300 m, 800 m) a point of maximum constructive interference, maximum destructive interference, or something in between?

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Textbook Question

Two strings are adjusted to vibrate at exactly 200 Hz. Then the tension in one string is increased slightly. Afterward, three beats per second are heard when the strings vibrate at the same time. What is the new frequency of the string that was tightened?

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Textbook Question

A 2.0-m-long string vibrates at its second-harmonic frequency with a maximum amplitude of 2.0 cm. One end of the string is at x = 0 cm. Find the oscillation amplitude at x = 10, 20, 30, 40, and 50 cm.

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Textbook Question

A violinist places her finger so that the vibrating section of a 1.0 g/m string has a length of 30 cm, then she draws her bow across it. A listener nearby in a 20°C room hears a note with a wavelength of 40 cm. What is the tension in the string?

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