The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of m. Its name comes from its arms, each of which can function as a second hand (so that it makes one revolution every s). Find the speed of the passengers when the Ferris wheel is rotating at this rate.
Ch 05: Applying Newton's Laws
Young & Freedman Calc14th EditionUniversity PhysicsISBN: 9780321973610Not the one you use?Change textbook
Chapter 5, Problem 54d
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of m. Its name comes from its arms, each of which can function as a second hand (so that it makes one revolution every s). What then would be the passenger's apparent weight at the lowest point?
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Determine the centripetal acceleration of the passenger at the lowest point. The centripetal acceleration is given by the formula: , where is the tangential speed and is the radius of the Ferris wheel.
Calculate the tangential speed of the passenger. The tangential speed is related to the period of rotation and the radius by the formula: . Use the diameter of the Ferris wheel to find the radius , and the period .
Determine the net force acting on the passenger at the lowest point. At this point, the forces acting on the passenger are the gravitational force (downward) and the normal force (upward). The net force is the centripetal force required to keep the passenger moving in a circular path: .
Relate the normal force to the net force. At the lowest point, the normal force is greater than the gravitational force because it must provide the centripetal force in addition to balancing the passenger's weight. The relationship is: , or equivalently: .
Substitute the expressions for and into the equation for . This gives: . Simplify this expression to find the apparent weight of the passenger at the lowest point.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Centripetal Acceleration
Centripetal acceleration is the acceleration directed towards the center of a circular path that an object follows. It is necessary for maintaining circular motion and is calculated using the formula a_c = v^2 / r, where v is the tangential speed and r is the radius of the circular path. In the context of the Ferris wheel, this acceleration affects the forces acting on the passengers as they move along the circular trajectory.
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Apparent Weight
Apparent weight refers to the sensation of weight experienced by an object or person, which can differ from actual weight due to acceleration. It is influenced by the net forces acting on the object, including gravitational force and any additional forces due to motion, such as centripetal force. At the lowest point of the Ferris wheel, the apparent weight is the sum of the gravitational force and the centripetal force required to keep the passenger moving in a circle.
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Forces in Circular Motion
In circular motion, several forces interact to keep an object moving along a curved path. The key forces include gravitational force, which pulls objects downward, and the normal force, which acts perpendicular to the surface. At the lowest point of the Ferris wheel, the normal force is greater than the gravitational force, resulting in an increased apparent weight for the passengers due to the need for centripetal force to maintain circular motion.
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Related Practice
Textbook Question
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Textbook Question
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of m. Its name comes from its arms, each of which can function as a second hand (so that it makes one revolution every s). A passenger weighs N at the weight-guessing booth on the ground. What is his apparent weight at the highest and at the lowest point on the Ferris wheel?
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Textbook Question
The Cosmo Clock 21 Ferris wheel in Yokohama, Japan, has a diameter of m. Its name comes from its arms, each of which can function as a second hand (so that it makes one revolution every s). What would be the time for one revolution if the passenger's apparent weight at the highest point were zero?
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