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Ch.14 - Chemical Kinetics
Chapter 14, Problem 110

The following mechanism has been proposed for the gasphasereaction of chloroform 1CHCl32 and chlorine:Step 1: Cl21g2 Δ k1 k - 1 2 Cl1g2 1fast2Step 2: Cl1g2 + CHCl31g2 ¡k2 HCl1g2 + CCl31g2 1slow2Step 3: Cl1g2 + CCl31g2 ¡k3 CCl4 1fast2(a) What is the overall reaction?

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1
Identify the reactants and products in each step of the mechanism.
Write down the reactants and products for each step: Step 1: Cl2(g) -> 2 Cl(g), Step 2: Cl(g) + CHCl3(g) -> HCl(g) + CCl3(g), Step 3: Cl(g) + CCl3(g) -> CCl4(g).
Add up all the reactants and products from each step to find the overall reaction.
Cancel out any intermediates that appear on both sides of the equation. In this case, Cl(g) and CCl3(g) are intermediates.
Write the simplified overall reaction after canceling intermediates: Cl2(g) + CHCl3(g) -> HCl(g) + CCl4(g).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Reaction Mechanism

A reaction mechanism is a step-by-step description of the pathway through which reactants are converted into products. It outlines individual elementary steps, including the sequence of bond-breaking and bond-forming events. Understanding the mechanism helps in predicting the rate of reaction and the overall stoichiometry of the process.
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Reaction Mechanism Overview

Rate-Determining Step

The rate-determining step (RDS) is the slowest step in a reaction mechanism that controls the overall reaction rate. In the provided mechanism, the second step is identified as slow, indicating that it is the RDS. Recognizing the RDS is crucial for understanding how changes in conditions can affect the reaction rate.
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Overall Reaction Equation

The overall reaction equation summarizes the net change from reactants to products, combining all elementary steps while canceling out intermediates. To derive the overall reaction from the mechanism, one must add the individual steps and eliminate any species that appear on both sides of the equation, leading to a balanced representation of the chemical transformation.
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Related Practice
Textbook Question

The gas-phase decomposition of ozone is thought to occur by the following two-step mechanism.

Step 1: O3(g) ⇌ O2(g) + O(g) (fast)

Step 2: O(g) + O3(g) → 2 O2 (slow)

(a) Write the balanced equation for the overall reaction.

Textbook Question

The gas-phase decomposition of ozone is thought to occur by the following two-step mechanism.

Step 1: O3(g) ⇌ O2(g) + O(g) (fast)

Step 2: O(g) + O3(g) → 2 O2 (slow)

(b) Derive the rate law that is consistent with this mechanism. (Hint: The product appears in the rate law.)

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Textbook Question

The gas-phase decomposition of ozone is thought to occur by the following two-step mechanism.

Step 1: O3(g) ⇌ O2(g) + O(g) (fast)

Step 2: O(g) + O3(g) → 2 O2 (slow)

(d) If instead the reaction occurred in a single step, would the rate law change? If so, what would it be?

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Textbook Question

The following mechanism has been proposed for the gasphase reaction of chloroform 1CHCl32 and chlorine:

Step 1: Cl2(g) k1⇌ k-1 2 Cl(g) (fast)

Step 2: Cl(g) + CHCl3(g) k2→ HCl(g) + CCl3(g) (slow)

Step 3: Cl(g0 + CCl3(g) k3→ CCl4 (fast)

(e) What is the rate law predicted by this mechanism? (Hint: The overall reaction order is not an integer.)

Textbook Question

In a hydrocarbon solution, the gold compound (CH3)3AuPH3 decomposes into ethane (C2H6) and a different gold compound, (CH3)AuPH3. The following mechanism has been proposed for the decomposition of (CH3)3AuPH3:

Step 1: (CH3)3AuPH3 k1⇌k-1 (CH3)3Au + PH3 (fast)

Step 2: (CH3)3Au k2→ C2H6 + (CH3)Au (slow)

Step 3: (CH3)Au + PH3 k3→ (CH3)AuPH3 (fast)

(a) What is the overall reaction?

(b) What are the intermediates in the mechanism?