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Ch. 5 - Chromosome Mapping in Eukaryotes
Klug - Concepts of Genetics  12th Edition
Klug12th EditionConcepts of Genetics ISBN: 9780135564776Not the one you use?Change textbook
Chapter 5, Problem 17

Drosophila females homozygous for the third chromosomal genes pink and ebony (the same genes from Problem 16) were crossed with males homozygous for the second chromosomal gene dumpy. Because these genes are recessive, all offspring were wild type (normal). F1 females were testcrossed to triply recessive males. If we assume that the two linked genes, pink and ebony, are 20 mu apart, predict the results of this cross. If the reciprocal cross were made (F1 males—where no crossing over occurs—with triply recessive females), how would the results vary, if at all?

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Identify the genotypes of the parental flies: The females are homozygous recessive for pink and ebony on chromosome 3 (pp ee) and wild type for dumpy on chromosome 2 (DD), while the males are homozygous recessive for dumpy (dd) and wild type for pink and ebony (P E).
Determine the F1 genotype: Since pink and ebony are recessive and on the same chromosome, and dumpy is on a different chromosome, the F1 females will be heterozygous for pink and ebony (Pp Ee) and heterozygous for dumpy (Dd). Because the parents are homozygous recessive for different genes, all F1 offspring will be phenotypically wild type.
Understand the testcross: The F1 females (Pp Ee Dd) are testcrossed to males homozygous recessive for all three genes (p e d). Since pink and ebony are linked with a recombination frequency of 20 mu (20%), calculate the expected frequency of parental and recombinant gametes from the F1 females.
Calculate gamete types from F1 females: For the linked pink and ebony genes, 80% of gametes will be parental types (P E and p e) and 20% recombinant types (P e and p E). For the unlinked dumpy gene, assume independent assortment, so half the gametes will carry D and half d.
Predict offspring phenotypes: Combine the gametes from F1 females with the recessive testcross male gametes (p e d) to determine the expected phenotypic ratios. For the reciprocal cross with F1 males (where no crossing over occurs), only parental types will be produced, so recombinant phenotypes will be absent.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Genetic Linkage and Recombination Frequency

Genetic linkage occurs when two genes are located close together on the same chromosome and tend to be inherited together. The recombination frequency, measured in map units (mu), indicates the likelihood of crossing over between these genes; 20 mu means a 20% chance of recombination. This concept helps predict offspring genotypes based on parental gene arrangements.
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Chi Square and Linkage

Testcross and Its Purpose

A testcross involves crossing an individual with a dominant phenotype but unknown genotype to a homozygous recessive individual. This reveals the genotype of the tested individual by analyzing offspring phenotypes, especially useful for detecting recombination events between linked genes.
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Sex Differences in Recombination in Drosophila

In Drosophila, crossing over occurs only in females, not in males. Therefore, recombination frequencies and offspring genotype ratios differ depending on whether the female or male parent carries the heterozygous chromosomes. This affects predictions of genetic outcomes in reciprocal crosses.
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Related Practice
Textbook Question

Another cross in Drosophila involved the recessive, X-linked genes yellow (y), white (w), and cut (ct). A yellow-bodied, white-eyed female with normal wings was crossed to a male whose eyes and body were normal but whose wings were cut. The F1 females were wild type for all three traits, while the F1 males expressed the yellow-body and white-eye traits. The cross was carried to an F2 progeny, and only male offspring were tallied. On the basis of the data shown here, a genetic map was constructed.

Could the F2 female offspring be used to construct the map? Why or why not?

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Textbook Question

In Drosophila, Dichaete (D) is a mutation on chromosome III with a dominant effect on wing shape. It is lethal when homozygous. The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F₁ progeny, with a Dichaete phenotype, were backcrossed to the ebony, pink homozygotes. Using the results of this backcross shown in the table.

Diagram this cross, showing the genotypes of the parents and offspring of both crosses.

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Textbook Question

In Drosophila, Dichaete (D) is a mutation on chromosome III with a dominant effect on wing shape. It is lethal when homozygous. The genes ebony body (e) and pink eye (p) are recessive mutations on chromosome III. Flies from a Dichaete stock were crossed to homozygous ebony, pink flies, and the F1 progeny, with a Dichaete phenotype, were backcrossed to the ebony, pink homozygotes. Using the results of this backcross shown in the table,

What is the sequence and interlocus distance between these three genes?

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Textbook Question

In Drosophila, two mutations, Stubble (Sb) and curled (cu), are linked on chromosome III. Stubble is a dominant gene that is lethal in a homozygous state, and curled is a recessive gene. If a female of the genotype

is to be mated to detect recombinants among her offspring, what male genotype would you choose as a mate?

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Textbook Question

If the cross described in Problem 18 were made, and if Sb and cu are 8.2 map units apart on chromosome III, and if 1000 offspring were recovered, what would be the outcome of the cross, assuming that equal numbers of males and females were observed?

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Textbook Question

Are mitotic recombinations and sister chromatid exchanges effective in producing genetic variability in an individual? in the offspring of individuals?

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