Draw the condensed structural formula for the dinucleotide G C that would be in RNA.

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All right. Hello everyone. So this question is asking us to draw a structure representing the correct sequence for the dinucleotide AC in R and A. So first and foremost, let's talk about the three main components making up a nucleotide. The first is the nitrogenous base that identifies that particular nucleo type up. Next, we have a sugar backbone and the third component is a phosphate group. Now recall that both the phosphate group and the nitrogenous base are attached to the sugar backbone in the center of the structure. Now the phosphate group of one nucleotide is going to attach to the sugar backbone, the fort. So let's go ahead and talk about how that happened. But first, let's draw out the sugar backbone of RNA, which if you recall is rivals. So four rivals, right, let's go ahead and start by drawing out the characteristic five of a ring. And I'm also going to go ahead and shade these bonds more towards the front of the structure just to show some dimensionality. So here to the very right side of the structure, we have carbon number one prime, which if you recall is where the nitrogenous base attaches to the sugar backbone adjacent to it. We have the two prime carbon which has a hydroxy group pointing beneath the ring and a hydrogen atom pointing above the ring. The three prime carbon has the same thing. Now, if this was DNA, the sugar backbone of DNA, which is deoxyribose would not have a hydroxy group on the two prime carbon. But in any case, we also have a five prime carbon depicted above the ring itself with its own hydroxy group. OK. So here, what I'm actually going to do is copy this structure that I just drew to go ahead and finish the structures of both nucleotides. And then we're going to talk about how to combine them. So let's go ahead and add the rest of our components now because the nitrogenous base of both is different. Let's start with what they both have in common, which is that phosphate group. Now, the phosphate group is going to attach to the hydroxy oxygen of the five prime carbon. So I erased the bond to hydrogen and I'm gonna go ahead and replace that with a single bond to phosphorus from there. I would add the rest of the group structure. So that's two single bonds between phosphorus and oxygen with both oxygens having a negative charge as well as another oxygen double bonded to phosphorus as well. All right. So now let's fill in that nucleotide. Excuse me, that nitrogen is space. So our first one is going to be editing given the fact that it's the letter A as the symbol for that particular nucleotide. So as mentioned before, the nitrogenous bases are going to be attached to the one prime carbon of the rival sugar though this is true for deoxy rivals as well. So the hydrogen attached to the one prime carbon is pointing downwards and there's going to be a bond between carbon number one prime and the nitrogen of the base pointing above the ring. And so from there, we would go ahead and finish the structure of adenine, which if you recall is a pyrimidine nucleotide composed of two fused rings. In addition to these two few strings, we also have a free amino group attached to one of our carbons here. So now that completes the structure of or fresh nucleotide. So now let's add the second nitrogenous base. And so for the second nitrogenous base, I'm actually going to go ahead and start moving this particular nucleotide towards the bottom of the screen. And we'll discuss why in a moment for now, let's just go ahead and connect carbon number one here of rivals, 21 of the nitrogens in cytosine. Now, cytosine is a perimeter base, which means that it's composed of only one ring. But in addition to the ring structure, we have both a car bono group and a free amino group. All right. So now that we have the structures of our monomers let's go ahead and combine them together. Now, there's a very specific reason why I went ahead and moved the second nucleotide underneath the first one. And this is because the three prime hydroxy group is what connects to the phosphate group of the next nucleotide to combine them together. So what I'm going to do here is erase the negative charge on this particular oxygen in the phosphate group and go ahead and connect it to the three prime carbon of rivals. This is ultimately connecting the two nucleotides and completes the structure four are given. So there you have it. And so with that being said, thank you so very much for watching and I hope you found this helpful.

Draw the condensed structural formula for the dinucleotide G C that would be in RNA.

Verified video answer for a similar problem:

Key Concepts

Nucleotides

Condensed Structural Formula

Phosphodiester Bond