Use grouping to factor out the polynomial.
$2ab+4a+3b^2+6b$

• A. $\(\left\)(2a+3\(\right\))\(\left\)(b+2\(\right\))$
• B. $\(\left\)(2a+b\(\right\))\(\left\)(b+6\(\right\))$
• C. $\(\left\)(b+2\(\right\))\(\left\)(2a+3b\(\right\))$
• D. $\(\left\)(a+3b\(\right\))\(\left\)(2b+2\(\right\))$

Answer: (C)