Chlorine reacts with oxygen to form Cl2O7. (c) Would you expect Cl2O7 to be more reactive toward H+1aq2 or OH-1aq2?

Video transcript

Hey everyone in this example, we have romaine reacting with oxygen to form die bro. Mean helped oxide. We need to determine which of the below statement is correct for di bromine, helped oxide. So looking at our formula for Deborah mean helped oxide. We would recognize bromine based on its location on the periodic table as a non metal and we recognize oxygen also as a non metal. So we have two non metals bonded to one another, forming a non metallic compound. And we want to recall that when it comes to non metallic compounds, the greater the nonmetal character will correspond to a greater acidity for that compound. So because we have just a compound full of non metals, we would say that therefore this is going to be an acidic compound, specifically an acidic oxide. Due to the fact that we have a nonmetal roaming bonded to a non metal oxygen, which is an oxide. So we have an acidic oxide because we have a high amount of nonmetal character. So because we've identified die bro mean Penta oxide as an acid. We would recognize that it's going to react with a base and we would recall that a base can be represented by a molecule with O. H. So, so far based on what we've outlined, we can go ahead and rule out choice A and choice C. And now we're between choices B and D. Where we would also rule out Choice B. Because as we stated, we want our die bro mean Penta oxide acid to react with a base being hydroxide. And so it's going to react with hydroxide more than it would react with a proton. So D would be our final answer to complete this example. If you have any questions, please leave them down below. Otherwise, I'll see everyone in the next practice video.