Complete and balance the equation for each of the following reactions:
b. Zn(s) + HCl(aq) →

Question

Complete and balance the equation for each of the following reactions:

b. Zn(s) + HCl(aq) →

Accepted Answer

Welcome back, everyone. We need to provide the complete balanced chemical reaction for the following equation where we have solid cadmium reacting with hydrochloric acid. We're going to begin by categorizing our reactants beginning with solid cadmium, recognize that it is located in our transition metal D block on our periodic tables and is therefore considered a metal which forms a two plus C charge. Next, we have HCL hydrochloric acid, which we should recall is one of our memorized strong acids from our textbook and consisting of hydrogen, a nonmetal and chlorine, a nonmetal. We have two nonmetals bonded, which means that HCL is considered a covalent or molecular compound. So in this case, we can interpret that we have a reaction between a metal with an acid and recall that this type of reaction is going to be a single replacement where our metal would take the place of our CAD ion from our acid and we would form as a result hydrogen gas. And then our second product being a salt where our salt is formed from the combination of our metal atom. Now being bonded to an anion from our acid. So writing out our reaction we have solid cadmium reacting with hydrochloric acid. And on our product side, when our metallic cadmium replaces our ca ion hydrogen, we are left with hydrogen alone where in its standard state recall that hydrogen exists as a diatomic gas. So we have H two gas as our first product. Our second product is going to be our metal cadmium now bonded to our nonmetal chloride, which we should recall cadmium as we stated above exists as a two plus ion. So chlorine will have a subscript of two and that would give us our compound cadmium two chloride, which based on our solubility rules, we recall is a soluble chloride. So we give it the label A Q for aqueous. Now we need to ensure that this is a bounced reaction. So comparing our atoms cadmium hydrogen and chlorine on both sides of our reaction, we would observe that on our reactant side, we have one atom of cadmium hydrogen and chlorine. Whereas on our product side, we have one atom of cadmium given by the subscript of two in hydrogen gas, we have two atoms of hydrogen and given by the subscript of two in cadmium, two chloride, we have two atoms of chlorine. We're going to begin by balancing out our non hydrogen atoms. First being our imbalanced chlorine, we have two atoms of chlorine on the product side and only one on the reactant side. So in order to mend this, we're going to place a coefficient of two in front of our hydrochloric acid on our reactant side, which will now give us a total of two atoms of hydrogen on the reactant side and two atoms of chlorine on the reactant side now fully bouncing out our reaction. And so now with our coefficient added, we can say that our entire reaction is going to be that one mole of solid cadmium reacts with two moles of hydrochloric acid to produce one mole of hydrogen gas and one mole of cadmium two chloride. This entire equation with our coefficient of two is our final answer. I hope this made sense and let us know if you have any questions.

Complete and balance the equation for each of the following reactions:
b. Zn(s) + HCl(aq) →

Verified video answer for a similar problem:

Key Concepts

Balancing Chemical Equations

Types of Chemical Reactions

Reactants and Products

Complete and balance the equation for each of the following reactions:b. Zn(s) + HCl(aq) →

Verified video answer for a similar problem:

Key Concepts

Balancing Chemical Equations

Types of Chemical Reactions

Reactants and Products

Complete and balance the equation for each of the following reactions:
b. Zn(s) + HCl(aq) →