Draw the Fischer projection for the other enantiomer of a to b in problem 13.21.
a.
b.

Question

Draw the Fischer projection for the other enantiomer of a to b in problem 13.21.

a.

b. Fischer projection of xylulose, showing its structural formula with hydroxyl groups and a carbonyl group.

Accepted Answer

Welcome back everyone to another video propose the plausible facial projections of the Inan tumors of the following monosaccharide. We're given two structures. Let's begin with the first one. The easiest way to solve this problem is simply you remember that in an tumors are non superimposable mirror images of each other. So when we look at the first structure, we simply want to draw its mirror image. Now, how do we do that? First of all, we're going to begin with the vertical line itself, right? This line represents the bonds that are pointing down or basically that on dashes. And we simply want to add the two horizontal lines. We're not going to change the orientation of the top and the bottom substituents, we're just going to leave them as they are. So we have cho L the height and at the very bottom, we have chtoh. However, we want to flip the horizontal substituents, we we simply want to swap hydrogen and a wage for the first structure. So now A H is going to be on the left instead of the right hand side and hydro is going to be on the right hand side if we look at the next chiral carbon atom, we want to swap hydrogen with the hydroxy substituent. So now hydrogen is on the right and the hydroxy substituent is on the left. And we can clearly see that these two structures are mirror images of each other because we simply have corresponding substituents as reflections right relative to the mirror plane. And we have got the first structure. Now for the second one, we can apply the same logic, we can begin by drawing a vertical line. We are going to add co carbonel at the very top. Now let's start with the bottom. We are going to add C H2O H and move up. So basically, first of all, we are going to swap the positions of hydrogen and hydroxyl. So now instead of being on the right or the inan tumor hydroxy substituent is going to be on the left and hydrogen is going to be on the right. For the next chiral position, we are swapping hydroxy substituent and hygen again. So hydroxy is on the left and hygen is on the right for Carbonel. Well, we basically don't have any Carl carbon atom here. So we can actually draw it on the right or the left. It doesn't really matter or complete consistency. We can just draw it on the left side because we're drawing a mirror image right, but it doesn't really matter because that specific carbon does not have four different subscriptions. So it is irrelevant. We only want to focus on those chiral positions with four different subscriptions and those would be the structures of the Inan tumors. Thank you for watching.

Draw the Fischer projection for the other enantiomer of a to b in problem 13.21.
a.
b.

Verified video answer for a similar problem:

Key Concepts

Fischer Projection

Enantiomers

Chirality

Draw the Fischer projection for the other enantiomer of a to b in problem 13.21.a. b.

Verified video answer for a similar problem:

Key Concepts

Fischer Projection

Enantiomers

Chirality

Draw the Fischer projection for the other enantiomer of a to b in problem 13.21.
a.
b.