Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol:
b. pentanoic acid

Question

Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol:

b. pentanoic acid

Accepted Answer

Welcome back everyone to the structure of the ester produced when Hexon acid reacts with ethyl alcohol. First of all, let's go ahead and draw the structures for this problem. First of all, one of the starting materials is a carboxylic acid as the problem suggests. So we can begin by drawing an R coo H functional group. And because it's Hexon OIC acid, hex means six. So we're going to add six carbon atoms to the parent. We have one, we're adding the second one, the third one, the fourth one, the fifth one and the sixth carbon atom. So we have Axonic acid and we simply want to perform a reaction with ethyl alcohol. Ethyl means we have an alkyl group with two carbons. And alcohol means that we're adding, oh, what we notice is that this is an ification reaction in which an alcohol reacts with an acid. So we want to make sure that we add heat and a catalyst such as sulfuric acid. And essentially to predict the products, we have to understand that yes, one of the products is going to be an ester. Now, to draw that specific aster, we simply want to take the acid and we went to replace the hydrogen atom from o age where the al substitute coming from the alcohol, we have a total of two carbon atoms. So we're just going to bond an ethyl group to oxygen. And this is how we are getting an ether. And now, of course, our byproduct's going to be water. That's it. Let's label the final answer to this problem and conclude the video. Thank you for watching.

Draw the condensed structural formula for the ester formed when each of the following reacts with methyl alcohol:
b. pentanoic acid

Verified video answer for a similar problem:

Key Concepts

Esterification Reaction

Condensed Structural Formula

Pentanoic Acid