A sink drain can become clogged with solid fat such as glyceryl tristearate (tristearin).
c. How many milliliters of a 0.500 M NaOH solution are needed to completely react with 10.0 g of glyceryl tristearate (tristearin)?

Question

A sink drain can become clogged with solid fat such as glyceryl tristearate (tristearin).

c. How many milliliters of a 0.500 M NaOH solution are needed to completely react with 10.0 g of glyceryl tristearate (tristearin)?

Accepted Answer

Welcome back everyone. Glycerol, tral metate or Tral mein is commonly used in food products. And as a component in some pharmaceuticals determine the volume in milliliters of a 0.800 molar sodium hydroxide solution required to completely react with 15.0 g of Glycerol tral metate. First of all, what we're going to do is draw the structure of the given tr ayl glycerol. Let's begin with Glycerol itself. A three member gene, two hydrogens followed by one hydrogen and two hydrogens again. Right? Let's make sure that the second carbon is visible. And now we are going to draw three oxygens bonded to each carbon. We are replacing hydrogens from Glycerol, we Carbonis and those Carbonis essentially come from pic acid. In this case, we're given Glycerol tral metate, right. So we want to draw carbonel and we want to recall the structure of P metic acid. Essentially the side chain of palmitic acid will have a total of 15 carbons. You will have 14 C two repeating units followed by the terminal metal group. So a stray chain, it is fully saturated. And because it's tral metate, we have three of those according to the context of the problem, it reacts with sodium hydroxide. So we are observing a saponification reaction which needs heat and we have to recall that this is the hydrolysis of an ester. So we are producing an alcohol to begin with, which is as usually glycerol, right. So essentially we are breaking those carbon oxygen bonds, replacing those carbon oxygen bonds with carbon hydroxyl bonds. This is how we get glycerol as the first product and the second product in a saponification reaction. Well, that would be a carboxylate salt. Our carboxylate are all identical. So we will have three moles of carboxylate. And the counter I am is sodium sodium is the cat I am. And then we can simply draw the resultant or boxy late. Now, we want to balance the equation if we have we sodium C ions on the right. We also want to include we on the left and this essentially balances the equation. Now, what we want to understand is that we're given a mass of glycerol tral metate, let's call it GT. So the mass is 15.0 g. We want to identify the number of moles of this structure. And to do that, we want to evaluate the molar mass of the given glycerol tral metate to do that. We first of all want to understand that this structure has a total of 51 carbon atoms. It also has a total of 98 hydrogens. And for oxygens we have a total of six using the periodic table and the atomic mass for each, we can add those numbers together. And when we add the atomic masses, we end up with 807 point 2 9 4 g per mole. That's the molar mass of the given tr ayl glycerol. Now, to identify the number of moles, we know that the number of moles is simply the ratio between mass and molar mass. So in this case, our mass is 15.0 g and the molar mass is 807.294 g per mole. This gives us the number of moles of the starting structure. So let's evaluate the result. We end up with a 0.018 58 moles. Let's carry that extra significant figure. Now, what we want to do is simply calculate the volume of sodium hydroxide to do that, we need to evaluate the number of moles of sodium hydroxide. And as we can see, this is a 123 ratio reaction for every mole of Glycerol tral metate. We need three moles of NAOH, meaning the number of moles of NAOH would be we multiplied by the number of moles of Glycerol tray permitted. So we multiply by 0.018 58 moles and this gives us a total of 0.0 557 or mouse. Now, we know that this is a solution, right? Let's recall that the concentration of a solution is the ratio between moles and volume. So if we rearrange this formula, then the number of milliliters would be equal to the ratio between moles and concentration. Actually, we will get liters, right? We will need to convert that into milliliters. So volume of NH would simply be equal to the number of moles found previously 0055 74 moles divided by the given concentration or molarity, right. So the given molarity is 0.800 Mohler. And now we have to understand that this answer is going to be in liters. So we can immediately multiply by the conversion factor that gives us milliliters instead of liters. And we know that 1 mL is equal to sense the power of negative third of a liter. And when we perform this calculation, we end up with 69.7 mL, which is the final answer to the problem. Thank you for watching.

A sink drain can become clogged with solid fat such as glyceryl tristearate (tristearin).
c. How many milliliters of a 0.500 M NaOH solution are needed to completely react with 10.0 g of glyceryl tristearate (tristearin)?

Verified video answer for a similar problem:

Key Concepts

Stoichiometry

Molarity

Chemical Reaction of Saponification

A sink drain can become clogged with solid fat such as glyceryl tristearate (tristearin).c. How many milliliters of a 0.500 M NaOH solution are needed to completely react with 10.0 g of glyceryl tristearate (tristearin)?

Verified video answer for a similar problem:

Key Concepts

Stoichiometry

Molarity

Chemical Reaction of Saponification

A sink drain can become clogged with solid fat such as glyceryl tristearate (tristearin).
c. How many milliliters of a 0.500 M NaOH solution are needed to completely react with 10.0 g of glyceryl tristearate (tristearin)?