Use condensed structural formulas to write the balanced chemical equation for the hydrogenation of glyceryl trilinolenate, a fat containing glycerol and three linolenic acid molecules.

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Welcome back. Every once another video, rightly balanced chemical equation for the hydrogenation of trio A fat consisting of Glycerol and three Oleic acid molecules use condensed structural formulas. So for this specific problem, we're looking at tri ayl glycerol. And whenever we want to draw a structure, we began by drawing Glycerol which is a three member chain starting with CH two, followed by CH and another CH two. And we went to draw carbon oxygen bonds and simply replace hydrogen atoms coming from Glycerol wet carbonyl. And this is where the asset comes in, right, starting with Car Bono, we simply want to identify the alkyl groups bonded to carbonyl carbon. And because we're looking at we Oleic acid molecules, let's recall that Oleic acid has a general form of C 18 to 1, meaning it has 18 carbons and one double bond or one pie bond. And the most important part is to understand that this pi bond is between carbon sine and 10. So the pipe bomb starts at carbon number nine and extends towards carbon number 10. So what we want to do is simply draw eight carbons. We have carbona followed by seven carbons And because we're looking at a stray chain, we simply have repeating C two units. So ch 27 times. So this is the final carbon would be our eighth carbon because the first one comes from carbona. And now we want to draw carbon number nine, which is going to be CH because it's double bonded to carbon number 10, right? So we don't have that extra hydrogen. So now how many carbons do we have? Eight plus two gives us TEM. And because our chain is going to end with C three with the terminal metal group, we simple ones to understand how many S two units we have in between. So 18 minus 1, 17 minus 7, 10 minus 28 minus one from the muscle group. Well, this gives us seven sees two units. And we simply want to draw the remaining side chains, which will be the same chains, right? Because we have three of those. So we have the starting material. And from here, we simply want to draw the product of hydrogenation reaction. Let's recall that a hydrogenation reaction is simply a reduction reaction which allows us to reduce the double bonded carbons. Simply speaking, we are only interested in carbon carbon, double bonds, not carbon oxygen double bonds. Because to reduce those, we need different conditions, not atypical hydrogenation reaction. So essentially what we're doing is breaking the py bonds and adding two hydrogen atoms to the originally double bonded carbons. And as we understand, they become CH two units, right? And let's recall that the region for hydrogenation is two in the presence of a transition metal catalyst such as palladium. And since we need to add a total of 123456 hydrogen atoms, we need three molecules of two because each molecule has two hydrogen atoms. Now how do we draw the product while we can begin with Glycerol? Once again, ch two Chch two followed by oxygen for each carbon, followed by carbel. And now the product is going to look much simpler because we only have repeating siege to units. We originally had seven plus seven. This gives us 14 and now we have two more in between. So we have a total of 16 siege two units followed by CH three since we have removed that pi bond from each side chain, and we can just repeat the process for the remaining parts of the final product. And this gives us the final equation. It's already balanced, right? We have, we, most of hydrogen palladium is a catalyst. So there's no necessity to worry about it and that's it. Thank you for watching.

Use condensed structural formulas to write the balanced chemical equation for the hydrogenation of glyceryl trilinolenate, a fat containing glycerol and three linolenic acid molecules.

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Key Concepts

Hydrogenation

Condensed Structural Formula

Balanced Chemical Equation