Use the density values in TABLE 2.8 to solve each of the following problems:
a. A graduated cylinder contains 18.0 mL of water. What is the new water level, in milliliters, after 35.6 g of silver metal is submerged in the water?

Question

Use the density values in TABLE 2.8 to solve each of the following problems:

Table displaying the densities of various substances, including solids, liquids, and gases at specified temperatures.

a. A graduated cylinder contains 18.0 mL of water. What is the new water level, in milliliters, after 35.6 g of silver metal is submerged in the water?

Accepted Answer

Welcome back everyone. A 86.4 g mass of tungsten metal is placed into a graduated cylinder containing 32.3 mL of water determine the new water level in the graduated cylinder in milliliters. If the density of tungsten metal is 19.3 g per milliliter. So far, we know that our initial volume V I of our water in our cylinder is equal to 32.3 mL as given from the prompt. Now, we need to figure out VF of the water in the cylinder because we don't know that. And so that is going to equal the initial water level plus our volume of our Tungsten metal. So recall that tungsten is represented by the chemical symbol W now we only know Tungsten's density as well as its mass. And we want to recall our formula which relates density represented by row equal to mass over volume. And so what we would find is that for the density or rather for the volume of tungsten, we're going to multiply both sides of the equation by volume to cancel out volume, we're going to then have row times volume. I'm sorry, they should say times here. So row times volume equal to mass and to divide by both sides by row, we're now going to have volume isolated. And this is going to give us volume equal to mass divided by density. So for our volume of tungsten, we would plug in its mass from the prompt as 86.4 g in the numerator divided by its density given in the prompt as a 19.3 g per milliliter in our denominator. So notice that we can cancel our units of grams with grams in the denominator leaving us with milliliters as our final unit of volume. And what we'll find is that our volume of tungsten is equal to 4.4767 mL. So now that we have our volume of tungsten, we're going to find our final volume in the graduated cylinder of the water equal to our initial volume of the water in the cylinder given as 32.3 mL plus our volume of tungsten which we just found above as 4.4767 mL. And from this sum, we'll find our volume of the water at its final level being 36.7767 mL. And notice that in each of our measurements given in the prompt, we have a total of three significant figures. So we're going to round our answer to about three sig figs as 36.8 mL and this would be our final answer as our final volume of water in the graduated cylinder. Once tungsten is added, this corresponds to choice B in the multiple choice 36.8 millilitres. I hope this made sense and let us know if you have any questions.

Use the density values in TABLE 2.8 to solve each of the following problems:

a. A graduated cylinder contains 18.0 mL of water. What is the new water level, in milliliters, after 35.6 g of silver metal is submerged in the water?

Verified video answer for a similar problem:

Key Concepts

Density

Volume Displacement

Graduated Cylinder