A giant water tank takes the shape of a cylinder. It has a radius of $2$ $m$ and a height of $5m$. How much water can this tank hold? Round to the nearest tenth of a $m^3$.
Cylinder: $V=\pi r^{2}h$

• A. $125.7m^3$
• B. $157.1m^3$
• C. $62.8m^3$
• D. $251.3m^3$

Answer: (C)

Verified step by step guidance

1. Identify the formula for the volume of a cylinder, which is given by \(V = \pi r^2 h\), where \(r\) is the radius and \(h\) is the height.
2. Substitute the given values into the formula: radius \(r = 2\) meters and height \(h = 5\) meters, so the volume formula becomes \(V = \pi \times (2)^2 \times 5\).
3. Calculate the square of the radius: \((2)^2 = 4\), so the formula now is \(V = \pi \times 4 \times 5\).
4. Multiply the constants: \(4 \times 5 = 20\), so the volume formula simplifies to \(V = 20\pi\) cubic meters.
5. To find the numerical value, multiply \(20\) by the approximate value of \(\pi\) (about 3.1416), then round the result to the nearest tenth to get the volume in cubic meters.