Find the solution(s) using the quadratic formula.
$4 x^{2} - 4 x + 1 = 0$

$x=$\frac$12$

$x=-$\frac$12$

$x=1,x=$\frac$12$

$x=1,x=-$\frac$12$

Verified step by step guidance

Identify the coefficients from the quadratic equation \$4x^2 - 4x + 1 = 0$. Here, $a = 4$, $b = -4$, and $c = 1$.

Recall the quadratic formula: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$.

Calculate the discriminant $\Delta = b^2 - 4ac$ by substituting the values: $\Delta = (-4)^2 - 4 \times 4 \times 1$.

Evaluate the square root of the discriminant: $\sqrt{\Delta}$.

Substitute $b$, $\sqrt{\Delta}$, and $a$ into the quadratic formula to find the two solutions: $x = \frac{-(-4) \pm \sqrt{\Delta}}{2 \times 4}$.

Master Introduction to the Quadratic Formula with a bite sized video explanation from Patrick Ford

Find the solution(s) using the quadratic formula.4x2−4x+1=04x^2-4x+1=0