Ethyl octanoate is a flavor component of mangoes.
e. How many milliliters of a 0.315 M NaOH solution is needed to completely hydrolyze (saponify) 2.84 g of ethyl octanoate?

Question

Ethyl octanoate is a flavor component of mangoes.

e. How many milliliters of a 0.315 M NaOH solution is needed to completely hydrolyze (saponify) 2.84 g of ethyl octanoate?

Accepted Answer

Welcome back everyone. Iso amy acetate has a banana like odor and is used in flavoring. Calculate the volume in milliliters of a 0.400 molar potassium hydroxide solution needed to fully sify 4.20 g of iso amyl acetate. And we're given the molecular formula of iso amyl acetate. What we're going to do in this problem is first, we'll visualize what type of an ester we have. Since it is acid date, we simply want to draw a two member chain within the parent. And then for the alcoy part, while we have 12, we four carbon atoms in the longest continuous chain. And then at the end, we have a muscle substituent iso ML group, right? So essentially what we are doing here is performing a base catalyzed hydrolysis with potassium hydroxide. So essentially what we are trying to do here is simply form two different products. Let's recall that one of them is going to be a carboxylate salt, which is obtained from the carbona part. We are simply replacing the oxygen with the negatively charged oxygen and that negative charge is balanced by the potassium cion. And now the alcoy part warms the alcohol we're going to have, oh and then we're going to draw our four member chain, 123 and four carbons with a muscle group. And as we can see, it is a 1 to 1 reaction, right base catalyzed hydrolysis of any ester is essentially a 1 to 1 reaction. Meaning one mole of the ester reacts with one mole of the base. Meaning we can say that in order to fully sify iso amyl acetate, we will need the same number of moles of the base. So we can state that N one is equal to N two, the number of moles of ester must be equal to the number of moles of the base. Now, since we're given the mass of iso amyl acetate, we're going to express the number of moles in terms of mass M one in the molar mass capital M one, the ratio between mass and molar mass is simply equal to moles. And we know that this must be equal to the number of moles of potassium hydroxide expressed in terms of molarity, which is C right. So if we multiply molarity C by volume V, we're going to get the number of moles. So this is just another formula for most. And we got our relationship. Now, we can rearrange this relationship for volume B two, which is the volume of koh. So dividing both sides by C two, we can see that V two is simply M one divided by the product between C two and capital M one. All that we want to do here is simply substitute the givens the mass of iso amyl acetate is 4.20 g. And then for the denominator, we're going to put 0.400 molar for concentration. And for the molar mass, well, we're given the molecular formula, we can identify the molar mass of iso amyl acetate as 130 point 19 g per mole. Now, when we perform the given calculation, we also want to essentially convert this into milliliters. The answer is going to be obtained in liters. So we simply can use a conversion factor. We know that 1 L is equivalent to 1000 mL right now. Is that correct? Well, no, we essentially want to get milliliters on top, right. This is the desired quantity. So we're going to use 1 mL on top, which is equivalent to 10, the power of negative third of a leader and outperforming this calculation, we're going to get 80 0.7 mL of potassium hydroxide solution required. Thank you for watching.

Ethyl octanoate is a flavor component of mangoes.
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e. How many milliliters of a 0.315 M NaOH solution is needed to completely hydrolyze (saponify) 2.84 g of ethyl octanoate?

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Key Concepts

Saponification Reaction

Molarity (M)

Stoichiometry