To solve the equation where the sine of theta equals \( \frac{1}{2} \), we start by identifying the angles on the unit circle where this condition holds true. The sine function is positive in the first and second quadrants. Specifically, we find that \( \theta = \frac{\pi}{6} \) and \( \theta = \frac{5\pi}{6} \) are the angles corresponding to this sine value.

Next, we convert these radian measures into degrees. The conversion from radians to degrees can be achieved using the formula:

\( \text{Degrees} = \text{Radians} \times \frac{180}{\pi} \)

Applying this to our angles:

For \( \frac{\pi}{6} \):

\( \frac{\pi}{6} \times \frac{180}{\pi} = \frac{180}{6} = 30 \text{ degrees} \)

For \( \frac{5\pi}{6} \):

\( \frac{5\pi}{6} \times \frac{180}{\pi} = \frac{5 \times 180}{6} = 150 \text{ degrees} \)

Now that we have the angles in degrees, we need to express all possible solutions. Since the sine function is periodic, we can add full rotations to our solutions. In degrees, a full rotation is \( 360 \) degrees. Therefore, we express the general solutions as:

\( \theta = 30 + 360n \) and \( \theta = 150 + 360n \)

where \( n \) is any integer. This accounts for all angles that satisfy the original equation.