Exercises 41–60 contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These are the restrictions on the variable. b. Keeping the restrictions in mind, solve the equation. 1/(x - 1) + 5 = 11/(x - 1)
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
Problem 53
Textbook Question
Solve each equation for x. x/(a-1) = ax+3
Verified step by step guidance1
Start with the given equation: \(\frac{x}{a} - 1 = ax + 3\).
To eliminate the fraction, multiply every term on both sides of the equation by \(a\) to get rid of the denominator: \(a \times \left( \frac{x}{a} - 1 \right) = a \times (ax + 3)\).
Simplify both sides: on the left, \(a \times \frac{x}{a} = x\) and \(a \times (-1) = -a\); on the right, \(a \times ax = a^2 x\) and \(a \times 3 = 3a\). So the equation becomes \(x - a = a^2 x + 3a\).
Next, collect all terms involving \(x\) on one side and constants on the other side. For example, subtract \(a^2 x\) from both sides and add \(a\) to both sides: \(x - a^2 x = 3a + a\).
Factor out \(x\) on the left side: \(x(1 - a^2) = 4a\). Finally, solve for \(x\) by dividing both sides by \((1 - a^2)\): \(x = \frac{4a}{1 - a^2}\).
Verified video answer for a similar problem:This video solution was recommended by our tutors as helpful for the problem above
Video duration:
3mPlay a video:
Was this helpful?
Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solving Linear Equations
Solving linear equations involves isolating the variable on one side of the equation using inverse operations such as addition, subtraction, multiplication, and division. The goal is to find the value of the variable that makes the equation true.
Recommended video:
Solving Linear Equations with Fractions
Working with Fractions in Equations
When an equation contains fractions, it is often helpful to eliminate the denominators by multiplying both sides by the least common denominator. This simplifies the equation and makes it easier to solve for the variable.
Recommended video:
Solving Linear Equations with Fractions
Distributive Property
The distributive property allows you to multiply a single term by each term inside parentheses, expressed as a(b + c) = ab + ac. This property is useful for expanding expressions and simplifying equations before solving.
Recommended video:
Guided course
Multiply Polynomials Using the Distributive Property
Watch next
Master Introduction to Solving Linear Equtions with a bite sized video explanation from Patrick
Start learningRelated Videos
Related Practice
Textbook Question
1161
views
