In Exercises 103–114, factor completely. x4−5x2y2+4y4
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0. Review of Algebra
Factoring Polynomials
Problem 113
Textbook Question
Factor by any method. See Examples 1–7.
Verified step by step guidance1
Recognize that the expression \( (x+y)^2 - (x-y)^2 \) is a difference of squares, which can be factored using the formula \( a^2 - b^2 = (a-b)(a+b) \). Here, let \( a = (x+y) \) and \( b = (x-y) \).
Apply the difference of squares formula: \( (x+y)^2 - (x-y)^2 = ((x+y) - (x-y))((x+y) + (x-y)) \).
Simplify the first factor: \( (x+y) - (x-y) = x + y - x + y = 2y \).
Simplify the second factor: \( (x+y) + (x-y) = x + y + x - y = 2x \).
Write the fully factored form as the product of the two simplified factors: \( 2y \times 2x = 4xy \). So the factored form is \( (2y)(2x) \) or simply \( 4xy \).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Difference of Squares
The difference of squares is a factoring technique where an expression of the form a² - b² can be factored into (a - b)(a + b). Recognizing this pattern allows for quick simplification of expressions involving squared terms subtracted from each other.
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Binomial Expansion
Binomial expansion involves expanding expressions like (x + y)² into x² + 2xy + y². Understanding how to expand binomials helps in identifying terms and simplifying expressions before factoring.
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Factoring by Grouping
Factoring by grouping is a method where terms are grouped to find common factors, making it easier to factor complex expressions. This technique is useful when expressions do not immediately fit standard factoring formulas.
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