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Ch. 5 - Systems and Matrices
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 6, Problem 19

Find the partial fraction decomposition for each rational expression. See Examples 1–4. (x2)/(x2 + 2x + 1)

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1
First, recognize that the denominator \(x^2 + 2x + 1\) can be factored. Factor it as \(\left(x + 1\right)^2\) because it is a perfect square trinomial.
Rewrite the rational expression using the factored denominator: \(\frac{x^2}{\left(x + 1\right)^2}\).
Set up the partial fraction decomposition form for a repeated linear factor \(\left(x + 1\right)^2\). The general form is: \(\frac{A}{x + 1} + \frac{B}{\left(x + 1\right)^2}\), where \(A\) and \(B\) are constants to be determined.
Multiply both sides of the equation by the common denominator \(\left(x + 1\right)^2\) to clear the fractions: \(x^2 = A(x + 1) + B\).
Expand the right side and collect like terms: \(x^2 = A x + A + B\). Then, equate the coefficients of corresponding powers of \(x\) on both sides to form a system of equations to solve for \(A\) and \(B\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Partial Fraction Decomposition

Partial fraction decomposition is a method used to express a rational function as a sum of simpler fractions. This technique is especially useful for integrating rational functions or simplifying complex expressions. It involves breaking down a fraction into components with denominators that are factors of the original denominator.
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Factoring Quadratic Expressions

Factoring quadratic expressions involves rewriting a quadratic polynomial as a product of two binomials. For example, x^2 + 2x + 1 factors to (x + 1)^2. Recognizing and factoring the denominator is essential in partial fraction decomposition to determine the form of the simpler fractions.
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Handling Repeated Factors in Denominators

When the denominator has repeated factors, such as (x + 1)^2, the partial fraction decomposition must include terms for each power of the repeated factor. For (x + 1)^2, the decomposition includes terms with denominators (x + 1) and (x + 1)^2, each with its own numerator to solve for.
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