Use substitution to solve the following system of linear equations.
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
7. Systems of Equations & Matrices
Two Variable Systems of Linear Equations
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Solve the following system of equations. Classify it as CONSISTENT (INDEPENDENT or DEPENDENT) or INCONSISTENT.
2x+8y=7
x+4y=19
A
Consistent and Independent
B
Consistent and Dependent
C
Inconsistent
Verified step by step guidance1
Step 1: Start by writing down the given system of equations. The first equation is \(2x + 8y = 7\) and the second equation is \(x + 4y = 19\).
Step 2: To solve the system, we can use the method of elimination. First, multiply the second equation by 2 to align the coefficients of \(x\) in both equations. This gives us \(2x + 8y = 38\).
Step 3: Now, subtract the first equation \(2x + 8y = 7\) from the modified second equation \(2x + 8y = 38\). This will eliminate \(x\) and \(y\) terms, resulting in \(0 = 31\).
Step 4: The equation \(0 = 31\) is a contradiction, indicating that there is no solution to the system of equations. This means the system is inconsistent.
Step 5: Since the system is inconsistent, it does not have any solutions, and therefore cannot be classified as consistent (independent or dependent).
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Two Variable Systems of Linear Equations practice set

