Solve for x: x^(5/6) + x^(2/3) - 2x^(1/2) = 0
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- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
0. Review of Algebra
Rational Exponents
Problem 76
Textbook Question
Solve each equation. See Example 7. x5/4 = 32
Verified step by step guidance1
Identify the equation given: \(x^{\frac{5}{4}} = 32\).
To isolate \(x\), raise both sides of the equation to the reciprocal power of \(\frac{5}{4}\), which is \(\frac{4}{5}\). This step will help eliminate the fractional exponent on \(x\). So, write: \(\left(x^{\frac{5}{4}}\right)^{\frac{4}{5}} = 32^{\frac{4}{5}}\).
Simplify the left side using the property of exponents: \(\left(a^{m}\right)^{n} = a^{m \cdot n}\). This gives \(x^{\left(\frac{5}{4} \times \frac{4}{5}\right)} = x^{1} = x\).
Now, focus on simplifying the right side: \$32^{\frac{4}{5}}\(. Express 32 as a power of 2, since \)32 = 2^{5}\(, then rewrite the expression as \)\left(2^{5}\right)^{\frac{4}{5}}$.
Use the exponent rule again to simplify: \(\left(2^{5}\right)^{\frac{4}{5}} = 2^{5 \times \frac{4}{5}} = 2^{4}\). This will give the value of \(x\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Exponents and Powers
Exponents indicate how many times a base number is multiplied by itself. Understanding how to manipulate exponents, including fractional exponents, is essential for solving equations like x^(5/4) = 32.
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Fractional Exponents
Fractional exponents represent roots and powers simultaneously; for example, x^(5/4) means the fourth root of x raised to the fifth power. Recognizing this helps in rewriting and solving the equation.
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Rational Exponents
Solving Exponential Equations
Solving exponential equations often involves isolating the variable by applying inverse operations such as taking roots or raising both sides to a reciprocal power. This process is key to finding the value of x in the given equation.
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