Precalculus
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Given the function f(x)=3(x2−1)f(x)=3(x^2-1), find the equation of the tangent line at x=1x=1.
y=−6x+6y=-6x+6
y=−6x−6y=-6x-6
y=6x+6y=6x+6
y=6x−6y=6x-6