Multiple ChoiceIdentify the most helpful first step in verifying the identity.sec3θ=secθ+tan2θcosθ\(\sec\)^3\(\theta\)=\(\sec\]\theta\)+\(\frac{\tan^2\theta}{\cos\theta}\)sec3θ=secθ+cosθtan2θ249views2rank
Multiple ChoiceIdentify the most helpful first step in verifying the identity.(tan2θsin2θ−1)=sec2θsin2(−θ)\(\left\)(\(\frac{\tan^2\theta}{\sin^2\theta}\)-1\(\right\))=\(\sec\)^2\(\theta\[\sin\)^2\(\left\)(-\(\theta\]\right\))(sin2θtan2θ−1)=sec2θsin2(−θ)255views5rank
Multiple ChoiceUse the even-odd identities to evaluate the expression.cos(−θ)−cosθ\(\cos\]\left\)(-\(\theta\[\right\))-\(\cos\]\theta\)cos(−θ)−cosθ375views9rank
Multiple ChoiceUse the even-odd identities to evaluate the expression.−cot(θ)⋅sin(−θ)-\(\cot\]\left\)(\(\theta\[\right\))\(\cdot\]\sin\[\left\)(-\(\theta\]\right\))−cot(θ)⋅sin(−θ)395views13rank
Multiple ChoiceSelect the expression with the same value as the given expression.sin(−38°)\(\sin\[\left\)(-38\(\degree\]\right\))sin(−38°)365views9rank
Multiple ChoiceUse the Pythagorean identities to rewrite the expression as a single term.(1+cscθ)(1−cscθ)\(\left\)(1+\(\csc\[\theta\]\right\))\(\left\)(1-\(\csc\[\theta\]\right\))(1+cscθ)(1−cscθ)370views10rank
Multiple ChoiceUse the Pythagorean identities to rewrite the expression with no fraction.11−secθ\(\frac{1}{1-\sec\theta}\)1−secθ1279views5rank
Multiple ChoiceSimplify the expression.tan2θ−sec2θ+1\(\tan\)^2\(\theta\)-\(\sec\)^2\(\theta\)+1tan2θ−sec2θ+1307views4rank