Table of contents
- 0. Fundamental Concepts of Algebra3h 29m
- 1. Equations and Inequalities3h 27m
- 2. Graphs1h 43m
- 3. Functions & Graphs2h 17m
- 4. Polynomial Functions1h 54m
- 5. Rational Functions1h 23m
- 6. Exponential and Logarithmic Functions2h 28m
- 7. Measuring Angles40m
- 8. Trigonometric Functions on Right Triangles2h 5m
- 9. Unit Circle1h 19m
- 10. Graphing Trigonometric Functions1h 19m
- 11. Inverse Trigonometric Functions and Basic Trig Equations1h 41m
- 12. Trigonometric Identities 2h 34m
- 13. Non-Right Triangles1h 38m
- 14. Vectors2h 25m
- 15. Polar Equations2h 5m
- 16. Parametric Equations1h 6m
- 17. Graphing Complex Numbers1h 7m
- 18. Systems of Equations and Matrices3h 6m
- 19. Conic Sections2h 36m
- 20. Sequences, Series & Induction1h 15m
- 21. Combinatorics and Probability1h 45m
- 22. Limits & Continuity1h 49m
- 23. Intro to Derivatives & Area Under the Curve2h 9m
11. Inverse Trigonometric Functions and Basic Trig Equations
Inverse Sine, Cosine, & Tangent
Struggling with Precalculus?
Join thousands of students who trust us to help them ace their exams!Watch the first videoMultiple Choice
Evaluate the expression.
cos−1(0)
A
0
B
2π
C
π
D
23π

1
Understand that \( \cos^{-1}(x) \) is the inverse cosine function, which gives the angle whose cosine is \( x \).
Recognize that the problem asks for \( \cos^{-1}(0) \), meaning we need to find the angle \( \theta \) such that \( \cos(\theta) = 0 \).
Recall that the cosine of an angle is 0 at specific points on the unit circle. These points are \( \frac{\pi}{2} \) and \( \frac{3\pi}{2} \).
Since the range of the inverse cosine function \( \cos^{-1}(x) \) is \([0, \pi]\), we need to select the angle within this range.
Identify that \( \frac{\pi}{2} \) is within the range \([0, \pi]\), while \( \frac{3\pi}{2} \) is not. Therefore, \( \cos^{-1}(0) = \frac{\pi}{2} \).