In Exercises 107–108, write the standard form of the equation of ...

Question

In Exercises 107–108, write the standard form of the equation of the circle with the given center and radius. Center (-2. 4), r = 6

Accepted Answer

Welcome back. I'm so glad you're here. We've got a circle and we know that its center is at 02. We know that the center of a circle is H. K. So R H equals zero and r K equals two and it has a radius of 12, so R equals 12. We want it in standard form, we recall from previous lessons that standard form it for a circle is going to be x minus H squared plus Y minus K squared equals R squared. So we've identified our H. And our K. And R. R. And let's just plug those in. So we know that the parentheses and the X stay the same and the minus R. H zero squared plus. Our parentheses are wise stays the same minus K. As to squared equals R. Which is 12 squared. And now we can just simplify a little bit X minus zero. That's just X. So we can write X squared plus and we'll keep y minus two squared equals 12 squared. Well that's 144. We look at our answer choices and this is going to match with answer choice B. Well done. We'll catch on the next one.

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