In Exercises 97–98, write the equation of each parabola in vertex form. Vertex: (-3,-1) The graph passes through the point (-2,-3).
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- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
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- 9. Sequences, Series, & Induction1h 22m
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4. Polynomial Functions
Quadratic Functions
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Graph the given quadratic function. Identify the vertex, axis of symmetry, intercepts, domain, range, and intervals for which the function is increasing or decreasing. f(x)=3x2+12x
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Identify the standard form of the quadratic function, which is f(x) = ax^2 + bx + c. In this case, f(x) = 3x^2 + 12x, where a = 3, b = 12, and c = 0.
Find the vertex of the parabola using the formula for the x-coordinate of the vertex, x = -b/(2a). Substitute a = 3 and b = 12 into the formula to find the x-coordinate.
Calculate the y-coordinate of the vertex by substituting the x-coordinate back into the function f(x). This gives you the vertex (h, k).
Determine the axis of symmetry, which is the vertical line that passes through the vertex. The equation for the axis of symmetry is x = h, where h is the x-coordinate of the vertex.
Identify the y-intercept by evaluating f(0). Since the function is f(x) = 3x^2 + 12x, substitute x = 0 to find the y-intercept. Also, find the x-intercepts by setting f(x) = 0 and solving for x.
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Quadratic Functions practice set

