Solve each rational inequality. Give the solution set in interval notation. (x + 1)/(x - 5) > 0
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Inequalities
Problem 58
Textbook Question
Solve each rational inequality. Give the solution set in interval notation. 20/(x - 1) ≥ 1
Verified step by step guidance1
Start by rewriting the inequality: \(\frac{20}{x - 1} \geq 1\).
Bring all terms to one side to have zero on the other side: \(\frac{20}{x - 1} - 1 \geq 0\).
Find a common denominator and combine the terms into a single rational expression: \(\frac{20 - (x - 1)}{x - 1} \geq 0\).
Simplify the numerator: \(\frac{21 - x}{x - 1} \geq 0\).
Determine the critical points by setting numerator and denominator equal to zero: \$21 - x = 0\( and \)x - 1 = 0$, then analyze the sign of the expression on intervals defined by these points to find where the inequality holds.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Rational Inequalities
Rational inequalities involve expressions where one or both sides contain rational functions, which are ratios of polynomials. Solving them requires finding values of the variable that make the inequality true, often by analyzing the sign of the expression and considering restrictions from denominators.
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Nonlinear Inequalities
Domain Restrictions
When solving rational inequalities, it is crucial to identify values that make the denominator zero, as these are excluded from the domain. These restrictions help determine critical points that divide the number line into intervals for testing the inequality.
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Interval Testing and Interval Notation
After finding critical points, the number line is divided into intervals. Each interval is tested to see if it satisfies the inequality. The solution set is then expressed in interval notation, which concisely represents all values that satisfy the inequality.
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