Write an equation in point-slope form and slope-intercept form for the line passing through (-2, -6) and perpendicular to the line whose equation is x − 3y+ 9 = 0.
Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
2. Graphs of Equations
Lines
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Graph a line with a slope of 0 that passes through the point (3,−2).
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Verified step by step guidance1
Understand that a line with a slope of 0 is a horizontal line. This means the line will run parallel to the x-axis.
Identify the point through which the line must pass, which is (3, -2). This point gives us the specific location on the graph where the line will intersect.
Since the line is horizontal, it will have the same y-coordinate for all x-values. Therefore, the equation of the line is y = -2.
Plot the point (3, -2) on the graph. This is where the line will pass through.
Draw a horizontal line through the point (3, -2) extending in both directions along the x-axis. This line represents the graph of the equation y = -2.
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