Solve each nonlinear system of equations. Give all solutions, including those with nonreal complex components. See Examples 1–5.
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- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
7. Systems of Equations & Matrices
Two Variable Systems of Linear Equations
Problem 37
Textbook Question
Solve each nonlinear system of equations. Give all solutions, including those with nonreal complex components.
2xy + 1 = 0
x + 16y = 2
Verified step by step guidance1
Start with the given system of equations:
\[2xy + 1 = 0\]
\[x + 16y = 2\]
From the second equation, solve for one variable in terms of the other. For example, solve for \[x\]:
\[x = 2 - 16y\]
Substitute the expression for \[x\] into the first equation to eliminate \[x\]:
\[2(2 - 16y)y + 1 = 0\]
Simplify the resulting equation to get a quadratic equation in terms of \[y\]:
\[2(2y - 16y^2) + 1 = 0\] which simplifies to \[4y - 32y^2 + 1 = 0\]
Solve the quadratic equation for \[y\] using the quadratic formula:
\[y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] where \[a = -32\], \[b = 4\], and \[c = 1\]. Then substitute each \[y\] value back into \[x = 2 - 16y\] to find the corresponding \[x\] values.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Nonlinear Systems of Equations
A nonlinear system involves at least one equation that is not linear, meaning variables may be multiplied together or raised to powers other than one. Solving such systems requires methods beyond simple substitution or elimination used for linear systems, often involving algebraic manipulation or substitution to reduce to a solvable form.
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Substitution Method
The substitution method involves solving one equation for one variable and then substituting that expression into the other equation. This reduces the system to a single equation with one variable, which can be solved using algebraic techniques, including handling nonlinear terms.
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Complex Solutions
When solving nonlinear systems, solutions may include complex numbers, especially if the equations lead to quadratic or higher-degree polynomials with no real roots. Understanding how to work with complex numbers, including imaginary units, is essential to find all possible solutions.
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