Write the partial fraction decomposition of each rational expression. 4x2 - 7x - 3/(x3 -x)
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Introduction to Matrices
Problem 14
Textbook Question
Write the partial fraction decomposition of each rational expression. 9x+21/(x² + 2x - 15)
Verified step by step guidance1
First, factor the denominator \(x^{2} + 2x - 15\). To do this, find two numbers that multiply to \(-15\) and add to \$2$.
Rewrite the denominator as the product of its factors: \((x + 5)(x - 3)\).
Set up the partial fraction decomposition for the rational expression \(\frac{9x + 21}{(x + 5)(x - 3)}\) as \(\frac{A}{x + 5} + \frac{B}{x - 3}\), where \(A\) and \(B\) are constants to be determined.
Multiply both sides of the equation by the denominator \((x + 5)(x - 3)\) to clear the fractions, resulting in \$9x + 21 = A(x - 3) + B(x + 5)$.
Expand the right side and then equate the coefficients of like terms (coefficients of \(x\) and the constant terms) on both sides to form a system of equations to solve for \(A\) and \(B\).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Partial Fraction Decomposition
Partial fraction decomposition is a method used to express a rational function as a sum of simpler fractions with denominators that are factors of the original denominator. This technique simplifies integration and other algebraic operations by breaking down complex fractions into manageable parts.
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Factoring Quadratic Expressions
Factoring quadratic expressions involves rewriting a quadratic polynomial as a product of two binomials. For example, x² + 2x - 15 factors into (x + 5)(x - 3). Factoring is essential in partial fraction decomposition to identify the denominators of the simpler fractions.
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Setting Up and Solving Systems of Equations
After expressing the rational expression as a sum of partial fractions, you equate numerators and solve for unknown coefficients. This process typically involves setting up a system of linear equations by matching coefficients of corresponding powers of x, which is crucial to find the values that complete the decomposition.
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