Table of contents
- 0. Review of Algebra4h 18m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations1h 43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 5m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 22m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Linear Equations
Problem 63
Textbook Question
In Exercises 61–66, find all values of x satisfying the given conditions. y1=5x−3,y2=4x−5,andy1−y2=1
Verified step by step guidance1
Start by writing down the given equations: \( y_1 = \frac{x - 3}{5} \), \( y_2 = \frac{x - 5}{4} \), and the condition \( y_1 - y_2 = 1 \).
Substitute the expressions for \( y_1 \) and \( y_2 \) into the equation \( y_1 - y_2 = 1 \) to get: \( \frac{x - 3}{5} - \frac{x - 5}{4} = 1 \).
Find a common denominator for the fractions on the left side, which is 20, and rewrite the equation as: \( \frac{4(x - 3)}{20} - \frac{5(x - 5)}{20} = 1 \).
Combine the fractions over the common denominator: \( \frac{4(x - 3) - 5(x - 5)}{20} = 1 \).
Multiply both sides of the equation by 20 to eliminate the denominator, then simplify and solve the resulting linear equation for \( x \).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Solving Linear Equations
Solving linear equations involves finding the value of the variable that makes the equation true. In this problem, you will combine expressions for y1 and y2 and solve for x by isolating the variable using algebraic operations like addition, subtraction, multiplication, or division.
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Solving Linear Equations with Fractions
Substitution Method
The substitution method involves replacing one variable with an equivalent expression from another equation. Here, y1 and y2 are given in terms of x, so you substitute these expressions into the equation y1 - y2 = 1 to form an equation with only x, simplifying the solving process.
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Choosing a Method to Solve Quadratics
Understanding Linear Functions
Linear functions are algebraic expressions where variables are to the first power and graph as straight lines. Recognizing that y1 and y2 are linear functions of x helps in setting up and solving equations involving their difference, as linearity ensures the operations and solutions remain straightforward.
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Introduction to Polynomial Functions
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Related Practice
Textbook Question
Solve each equation for x. a²x + 3x =2a²
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